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tester [92]
3 years ago
7

The ordered pair (a, b) gives the location of point P on the coordinate plane. The value of a is negative and the value of b is

zero. Where could point P be located on the coordinate plane?
Select one or more:
Quadrant I
Quadrant II
Quadrant IV
Quadrant III
x-axis
y-axis
Mathematics
2 answers:
Kaylis [27]3 years ago
8 0
If x is negative and y is zero the point would be located on the x-axis.
german3 years ago
7 0

Answer:

<h2>X-axis.</h2>

Step-by-step explanation:

Givens

  • We have point which coordinates are (a,b)
  • The value of a is negative.
  • The value of b is zero.

Now, remember that all coordinates with the form (a,0), represents points on the x-axis, because the y-coordinate is zero.

In this case, we have negative horizontal coordinates and a null vertical coordinate, like (-a,0).

This points is on the x-axis, because y-value is null. Actually, it's on the negative part of x-axis, because its horizontal coordinate is negative.

Therefore, the right answer is x-axis.

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A lottery game has balls numbered 1 through 21. What is the probability of selecting an even numbered ball or an 8? Round to nea
Viktor [21]

Answer: 0.476

Step-by-step explanation:

Let A = Event of choosing an even number ball.

B = Event of choosing an 8 .

Given, A lottery game has balls numbered 1 through 21.

Sample space: S= {1,2,3,4,5,6,7,8,...., 21}

n(S) = 21

Then, A= {2,4,6,8, 10,...(20)}

i.e. n(A)= 10

B= {8}

n(B) = 1

A∪B = {2,4,6,8, 10,...(20)} = A

n(A∪B)=10

Now, the probability of selecting an even numbered ball or an 8 is

P(A\cup B)=\dfrac{n(A\cup B)}{n(S)}

=\dfrac{10}{21}\approx0.476

Hence, the required probability =0.476

7 0
3 years ago
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alekssr [168]
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How do I simplify an expression
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gregori [183]
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