Answer:
<em>The molarity of the solution is 0,47 M</em>
Explanation:
Molarity is a concentration measurement that expresses the moles of solute (in this case NaOH) in 1 liter of solution (1000ml). First we calculate the mass of 1 mol of NaOH, to calculate the moles in 58.8 g of said compound:
Weight 1 mol NaOH= Weight Na + Weight O + Weight H=23 g + 16 g +1 g
Weight 1 mol NaOH= 40 g/mol
40 g ---1 mol NaOH
58,8g---x= (58,8g x 1 mol NaOH)/40g =1,47 mol NaOH
3,1 L solution ------1,47 mol NaOH
1 L solution --------x= (1 L solution x 1,47 mol NaOH)/3,1 L solution
<em>x= 0,47 mol NaOH ---> The molarity of the solution is 0,47 M</em>
Answer: Charles's law, Avogadro's law and Boyle's law.
Explanation:
Boyle's law is: at constant temperature PV = constant
Charles law is: at constant pressure V/T = constant
Avogadro's law is: at constant pressure ant temperature, equal volume of gases contain equal number of moles: V/n = constant
Ideal gas law: PV/nT = constant => PV = nT*constant = PV = nTR
Endocytosis is a type of bulk transport which involves the movement of large particles through the membrane in and out
Answer:
B
Explanation:
Valence electrons only involve in chemical bonding, since they are farthest from the nucleus. Hope this helps!
<h3>
Answer:</h3>
2.125 g
<h3>
Explanation:</h3>
We have;
- Mass of NaBr sample is 11.97 g
- % composition by mass of Na in the sample is 22.34%
We are required to determine the mass of 9.51 g of a NaBr sample.
- Based on the law of of constant composition, a given sample of a compound will always contain the sample percentage composition of a given element.
In this case,
- A sample of 11.97 g of NaBr contains 22.34% of Na by mass
A sample of 9.51 g of NaBr will also contain 22.345 of Na by mass
% composition of an element by mass = (Mass of element ÷ mass of the compound) × 100
Mass of the element = (% composition of an element × mass of the compound) ÷ 100
Therefore;
Mass of sodium = (22.34% × 9.51 g) ÷ 100
= 2.125 g
Thus, the mass of sodium in 9.51 g of NaBr is 2.125 g