Answer:
Entropy.
Explanation:
I really hope this is right! sorry if its wrong
Answer:
The cell grows into its full size
The cell copies it’s dna
Explanation:
hope this helps pls mark brainliest
Answer:
<u>Balanced equation:</u>
![Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)](https://tex.z-dn.net/?f=Pb%28NO_%7B3%7D%29_%7B2%7D%28aq%29%2BK_%7B2%7DCO_%7B3%7D%28aq%29%5Crightarrow%20PbCO_%7B3%7D%28s%29%2B2KNO_%7B3%7D%28aq%29)
Explanation:
The chemical reaction between Lead(II) Nitrate and potassium carbonate is as follows.
![Lead(II)Nitrate+Potassium\,carbonate \rightarrow Lead(III)\,\,carbonate+Potassium\,nitrate](https://tex.z-dn.net/?f=Lead%28II%29Nitrate%2BPotassium%5C%2Ccarbonate%20%5Crightarrow%20Lead%28III%29%5C%2C%5C%2Ccarbonate%2BPotassium%5C%2Cnitrate)
![Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)](https://tex.z-dn.net/?f=Pb%28NO_%7B3%7D%29_%7B2%7D%28aq%29%2BK_%7B2%7DCO_%7B3%7D%28aq%29%5Crightarrow%20PbCO_%7B3%7D%28s%29%2B2KNO_%7B3%7D%28aq%29)
<u>Ionic equation:</u>
![Pb^{2+}(aq)+2NO_{3}^{-}(aq)+2K^{+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)+K^{+}(aq)+2NO_{3}^{-}](https://tex.z-dn.net/?f=Pb%5E%7B2%2B%7D%28aq%29%2B2NO_%7B3%7D%5E%7B-%7D%28aq%29%2B2K%5E%7B%2B%7D%28aq%29%2BCO_%7B3%7D%5E%7B2-%7D%28aq%29%5CLeftrightarrow%20PbCO_%7B3%7D%28s%29%2BK%5E%7B%2B%7D%28aq%29%2B2NO_%7B3%7D%5E%7B-%7D)
Cancel the same ions on the both sides of the reaction.
The net ionic equation is as follows.
![Pb^{2+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)](https://tex.z-dn.net/?f=Pb%5E%7B2%2B%7D%28aq%29%2BCO_%7B3%7D%5E%7B2-%7D%28aq%29%5CLeftrightarrow%20PbCO_%7B3%7D%28s%29)
Answer:
one-half
Explanation:
cuz for a first order reaction is a half life independent of concentration and constant over time
Answer:
See explanation
Explanation:
The reaction that we are considering here is quite a knotty reaction. It is difficult to decide if the mechanism is actually E1 or E2 since both are equally probable based on the mass of scientific evidence regarding this reaction. However, we can easily assume that the methylenecyclohexane was formed by an E1 mechanism.
Looking at the products, one could convincingly assert that the reaction leading to the formation of the two main products proceeds via an E1 mechanism with the formation of a carbocation intermediate as has been shown in mechanism attached to this answer. Possible rearrangement of the carbocation yields the 3-methylcyclohexene product.