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3 years ago

Which particles give the nucleus its positive charge?

Physics

2 answers:

Neporo4naja [7]3 years ago

6 0

Answer: Protons give the nucleus a positive charge.

Explanation:

Protons - Gives of positive charge

Neutrons - Gives of neutral charge (No charge)

Electrons - Gives off negitive charge

nataly862011 [7]3 years ago

5 0

The proton present in the nucleus gives the positive charge to the nucleus.

<u>Explanation: </u>

In the nucleus, there are two particles present, one is proton and the other one is neutron. Neutron is neutral in charge or say, it has no charge. Proton has the positive charge.

Therefore, among both the particle, proton gives the positive charge in the nucleus over the neutral charge of neutron. Thereby, nucleus acquires the positive charge from the proton. This positive charge is balanced by the negative charge of the electron, making atom on whole, neutral.

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In which medium does light travel faster: one with a critical angle of 27.0° or one with a critical angle of 32.0°? Explain. (Fo

Eddi Din [679]

Answer:

Among those two medium, light would travel faster in the one with a reflection angle of $32^{\circ}$ (when light enters from the air.)

Explanation:

Let $v_{1}$ denote the speed of light in the first medium. Let $v_{\text{air}}$ denote the speed of light in the air. Assume that the light entered the boundary at an angle of $\theta_{1}$ to the normal and exited with an angle of $\theta_{\text{air}}$ . By Snell's Law, the sine of $\theta_{1}\!$ and $\theta_{\text{air}}\!$ would be proportional to the speed of light in the corresponding medium. In other words:

$\displaystyle \frac{v_{1}}{v_{\text{air}}} = \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})}$ .

When light enters a boundary at the critical angle $\theta_{c}$ , total internal reflection would happen. It would appear as if the angle of refraction is now $90^{\circ}$ . (in this case, $\theta_{\text{air}} = 90^{\circ}$ .)

Substitute this value into the Snell's Law equation:

$\begin{aligned}\frac{v_{1}}{v_{\text{air}}} &= \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})} \\ &= \frac{\sin(\theta_{c})}{\sin(90^{\circ})} \\ &= \sin(\theta_{c})\end{aligned}$ .

Rearrange to obtain an expression for the speed of light in the first medium:

$v_{1} = v_{\text{air}} \cdot \sin(\theta_{1})$ .

The speed of light in a medium (with the speed of light slower than that in the air) would be proportional to the critical angle at the boundary between this medium and the air.

For $0 < \theta < 90^{\circ}$ , $\sin(\theta)$ is monotonically increasing with respect to $\theta$ . In other words, for $\!\theta$ in that range, the value of $\sin(\theta)\!$ increases as the value of $\theta\!$ increases.

Therefore, compared to the medium in this question with $\theta_{c} = 27^{\circ}$ , the medium with the larger critical angle $\theta_{c} = 32^{\circ}$ would have a larger $\sin(\theta_{c})$ . such that light would travel faster in that medium.

4 0

3 years ago

the resolution of a camera or other optical system is determined by the relationship between what two scales?

Triss [41]

The resolution of a camera or other optical system is determined by the relationship between that two scales of Light waves of different wavelengths produce diverse colors.

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).

The distance between the crests or troughs of a wave motion is referred to as the wavelength () of light. 2. Frequency (f) - The frequency of a repeated event is the number of instances per unit of time. Frequency in the context of light is the number of wavelength repetitions per second.

To learn more about wavelength please visit -
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#SPJ4

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2 years ago

A force is something that ___ an object to ____

kap26 [50]

Answer:

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3 years ago

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ycow [4]

Answer:

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2 years ago

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