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3 years ago

Which particles give the nucleus its positive charge?

Physics

2 answers:

Neporo4naja [7]3 years ago

6 0

Answer: Protons give the nucleus a positive charge.

Explanation:

Protons - Gives of positive charge

Neutrons - Gives of neutral charge (No charge)

Electrons - Gives off negitive charge

nataly862011 [7]3 years ago

5 0

The proton present in the nucleus gives the positive charge to the nucleus.

<u>Explanation: </u>

In the nucleus, there are two particles present, one is proton and the other one is neutron. Neutron is neutral in charge or say, it has no charge. Proton has the positive charge.

Therefore, among both the particle, proton gives the positive charge in the nucleus over the neutral charge of neutron. Thereby, nucleus acquires the positive charge from the proton. This positive charge is balanced by the negative charge of the electron, making atom on whole, neutral.

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A uniform rod is set up so that it can rotate about a perpendicular axis at one of its ends. The length and mass of the rod are

igor_vitrenko [27]

Answer:

0.231 N

Explanation:

To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be

$\alpha = \frac{\theta}{t} = \frac{6.37}{9.87} = 0.6454 rad/s^2$

If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:

$I = \frac{mL^2}{3} = \frac{1.27*0.847^2}{3} = 0.303kgm^2$

According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is

$T = I\alpha = 0.303*0.6454 = 0.196 Nm$

So the force acting on the other end to generate this torque mush be:

$F = \frac{T}{L} = \frac{0.196}{0.847} = 0.231 N$

4 0

4 years ago

A man 6 feet tall walks at a rate of 5 feet per second away from a light that is 15 feet above the ground. When he is 10 feet fr

harina [27]

Answer:

$\frac{25}{3}ft/s$

Explanation:

Height of man= 6ft

Height of light=1 5ft

Let BC=x and CD=y

BD=x+y

Triangle ABD and ECD are similar

When two triangles are similar then the ratio of their corresponding sides are equal

$\frac{AB}{EC}=\frac{BD}{CD}$

$\frac{15}{6}=\frac{x+y}{y}$

$\frac{5}{2}=\frac{x+y}{y}$

$5y=2x+2y$

$5y-2y=2x$

$3y=2x$

Differentiate w.r.t t

$2\frac{dx}{dt}=3\frac{dy}{dt}$

We have $\frac{dx}{dt}=5ft/s$

Substitute the value then we get

$2\times 5=3\frac{dy}{dt}$

$\frac{dy}{dt}=\frac{2\times 5}{3}=10/3ft/s$

Rate at which the tip of shadow is moving= $\frac{dx}{dt}+\frac{dy}{dt}$

Rate at which the tip of shadow is moving= $5+\frac{10}{3}=\frac{15+10}{3}ft/s$

Rate at which the tip of shadow is moving= $\frac{25}{3}ft/s$

5 0

3 years ago

Two identical billiard balls traveling at the same speed have a head-on collision and rebound. If the balls had twice the mass,

Vinvika [58]

Answer:

a) No difference

Explanation:

Since the billiard balls are identical , they have the same mass. Also they have the same speed

Since the angular momentum is conserved and the total energy is conserved ( if we assume elastic collision)

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

where m= mass , vi= initial velocity , vf= final velocity

since m1=m2=m , vi1=vi2=vi

1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²

m * v i² = 1/2 m (v f1² +v f2² )

vi² = 1/2(v f1² +v f2² )

since the 2 balls are indistinguishable from each other (they have identical initial mass and velocity) there is no reason for a preferential speed for one of the balls and therefore its velocities must be equal . Thus vf1=vf2=vf

therefore

v i² = 1/2(v f1² +v f2² ) = v i1² = 1/2* 2vf² = vf²

and thus

vi= vf

in conclusion, there is no difference in speed after the rebound

4 0

3 years ago

Thermal conductors don’t have to be hot to transfer heat. Explain a situation when an ice cube would still transfer heat to anot

seraphim [82]

At absolute zero, all particle motion stops so it is easy to transfer energy.

4 0

3 years ago

You are using an 8 th order low-pass filter. Determine the roll-off achievable in the stop band, in dB/dec, and determine the ph

Andreas93 [3]

Answer: The complexity of filter is the order of the filter. Greater the order of the filter, more efficient the filter is. Roll of value of one filter is 20dB/dec. So the roll-off value of 8th order filter is 160dB/dec. 8th order filter is more efficient than the second order low-pass filter.

4 0

4 years ago