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DerKrebs [107]
3 years ago
5

Which is true about refraction from one material into a second material with a greater index of refraction when the incident ang

le is, say, 30º?
Physics
1 answer:
Kobotan [32]3 years ago
8 0
I believe the appropriate answer is that at the interface the ray bends way from the normal. 
When a ray enters a more dense substance or material (with higher refractive index) , it bends more towards the normal. The amount of bending depends on the change in speed such that is a substance causes the light to speed up or slow down more, it will refract more, and the other factor is the angle of incidence such that if the light is entering the substance at a greater angle, the amount of refraction will be more noticeable.
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When measuring speed, you will measure the
qaws [65]

Answer:

Speed is the rate at which an object's position changes, measured in meters per second. The equation for speed is simple: distance divided by time

Explanation:

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3 years ago
Where does groundwater come from?
jek_recluse [69]
Groundwater is the water found underground in the cracks and spaces in soil, sand and rock. It is stored in and moves slowly through geologic formations of soil, sand and rocks called aquifers.


Hope this helps.


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4 0
2 years ago
Read 2 more answers
Over the last several decades, scientists have addressed the problem of nonrenewable natural resources such as fossil fuels. Hum
ExtremeBDS [4]

Answer:

Option (C)

Explanation:

The nuclear energy is defined as a type of energy which liberates either by the process of nuclear fusion or nuclear fission and is mainly used to generate electricity. This energy is stored in the core of an atom (or nucleus).

It is highly effective, cost-effective and there is no emission of greenhouse gases.

But it also has some disadvantages, of which one is that it produces radioactive waste materials, which are difficult to dispose these substances and is also a very expensive method. These materials emit radiations that are harmful to the organisms. So, it is very challenging to dispose these radioactive waste materials.

Thus, the correct answer is option (C).

4 0
3 years ago
Read 2 more answers
A 1300-N crate rests on the floor. How much work is required to move it at constant speed (a)
kherson [118]

a) The work done is 920 J

b) The work done is 5200 J

Explanation:

a)

In this first part of the problem, the crate is moved horizontally at constant speed.

The work required in this case is given by

W=Fd cos \theta

where

F is the magnitude of the force applied

d is the displacement of the crate

\theta is the angle between the direction of the force and of the displacement

Here the crate is moved at constant speed: this means that the acceleration of the crate is zero, and so according to Newton's second law, the net force on the crate is zero: this means that the force applied, F, must be equal to the force of friction (but in opposite direction), so

F = 230 N

The displacement is

d = 4.0 m

And the angle is \theta=0^{\circ}, since the force is applied horizontally. Therefore, the work done is

W=(230)(4.0)(cos 0^{\circ})=920 J

b)

In this case, the crate is moved vertically. The force that must be applied to lift the crate must be equal to the weight of the crate (in order to move it a constant speed), therefore

F = W = 1300 N

The displacement this time is again

d = 4.0 m

And the angle is \theta=0^{\circ}, since the force is applied vertically, and the crate is moved also vertically. Therefore, the work done on the crate this time is

W=(1300)(4.0)(cos 0^{\circ})=5200 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

4 0
3 years ago
If two particles have equal charges and are placed near one another, how
navik [9.2K]

Answer: C) The two particles will move away from each other

Explanation:

When two electrically charged bodies come closer, appears a force that attracts or repels them, depending on the sign of the charges of this two bodies.

This is stated by Coulomb's Law:

"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them"  

Mathematically this law is written as:  

F_{E}= K\frac{q_{1}.q_{2}}{d^{2}}  

Where K is a proportionality constant.  

Now, if q_{1} and q_{2} have the same sign charge (both positive or both negative), a repulsive force will act on these charges.

5 0
3 years ago
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