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marusya05 [52]
3 years ago
10

Select the term that best describes the statement. A triangle is acute provided all the angles have a measure of less than 90 de

grees.
a) conjunction
b) disjunction
c) negation
d) conditional
Mathematics
2 answers:
vovangra [49]3 years ago
8 0

Answer:

The answer is conjunction

Step-by-step explanation:

There is a slight pause between acute and provided. the statement is also true.

beks73 [17]3 years ago
3 0
A...conjunction


hope this helps : )


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A + (b-4) when a-24 and b-7
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Answer:

a=24

b=7

now

24+(7-4)

24+3

27

so the answer is 27

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X-5y=2 and 4x+2y=8 using elimination
kobusy [5.1K]

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y=0  x=2

Step-by-step explanation:

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Solve −x+5≤4 or 2x+3≥−1 and write the solution in interval notation.
serg [7]

Answer:

Step-by-step explanation:

\left \{ {{-x+5\leq 4} \atop {2x+3\geq -1}} \right.   ⇒ x\geq 1\\2x\geq 4\\x\geq -2

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x \geq -2\\(-2,+ { \infty} ) (Answer)

6 0
2 years ago
The claim is that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0.10, and th
Alex777 [14]

Answer:

The correct option is b) 4.71

Step-by-step explanation:

Consider the provided information.

Test statistic for proportion: z=\frac{\hat p-p}{\sqrt{\frac{pq}{n}}}

It is given that the claim is that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0.10, and the sample statistics include n=800 deaths of the elderly with 15 percent of them attribute to residential falls.

Therefore, \hat p=0.15, p = 0.1, q = 1-0.1 = 0.9 and n = 800.

Substitute the respective values in the above formula.

z=\frac{0.15-0.1}{\sqrt{\frac{0.1\times0.9}{800}}}

z=\frac{0.05}{\sqrt{\frac{0.09}{800}}}

z\approx4.71

Hence, the correct option is b) 4.71

3 0
3 years ago
You recently sent out a survey to determine if the percentage of adults who use social media has changed from 66%, which was the
il63 [147K]

Answer:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Of the 2809 people who responded to survey, 1634 stated that they currently use social media.

This means that n = 2809, \pi = \frac{1634}{2809} = 0.5817

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 - 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.56

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5817 + 2.327\sqrt{\frac{0.5817*4183}{2809}} = 0.6034

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).

6 0
2 years ago
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