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Law Incorporation [45]
3 years ago
13

Which has the lowest freezing point?

Chemistry
1 answer:
Maslowich3 years ago
8 0
Freezing point depression depends of the number of particles of the solute in the solution.
1)Pure water have highest freezing point. All other solutions with given solutes will have lower temperatures. 
2) The more particles of the solute in the solution the lower freezing point is going to be.
<span>b. 1.0 m NaCl ( dissociates and give 2 mol ions (1 mol Na⁺ and 1 mol Cl⁻))
c. 1.0 m K3PO4 (</span>dissociates and give 4 mol ions (3 mol K⁺ and 1 mol PO4³⁻)<span>
d. 1.0 m CaCl2 (</span>dissociates and give 3 mol ions (1 mol Ca²⁺ and 2 mol Cl⁻))<span>
e. 1.0 m glucose (c6h12o6) (glucose does not dissociate, and solution have
1 mole of particles of the solute(glucose))

The largest number of particles has </span>1.0 m K3PO4  solution, and it is has lowest freezing point . Answer is C.
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B gas is produced is the answer.


8 0
3 years ago
Is C2S6 ionic or covalent
Stels [109]

Answer:

covalent

Explanation:

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8 0
3 years ago
If you have 1.1 moles of magnesium nitrate then how many grams is that
marysya [2.9K]

Answer: 162.8 grams

Explanation:

Magnesium nitrate has a chemical formula of Mg(NO3)2.

Given that:

Number of moles of Mg(NO3)2 = 1.1 moles

Mass in grams of Mg(NO3)2 = ?

For Molar mass of Mg(NO3)2, use atomic mass of magnesium = 24g, nitrogen = 14g, oxygen = 16g

Mg(NO3)2 = 24g + (14g + 16gx3) x 2

= 24g + (14g + 48g) x 2

= 24g + (62g) x 2

= 24g + 124g

= 148g/mol

Now, apply the formula:

Number of moles = Mass in grams / molar mass

1.1 moles = Mass / 148g/mol

Mass = 1.1 moles x 148g/mol

Mass = 162.8 grams

Thus, there are 162.8 grams of magnesium nitrate.

3 0
3 years ago
The density of gold is 19.32 g/mL. What is the volume, in mL, of a nugget of gold with a mass of 55.07 g?
Vika [28.1K]

Answer: 2.850

Explanation:

19.32=\frac{55.07}{v}\\19.32v=55.07\\v=\frac{55.07}{19.32}=\boxed{2.850 \text{ mL}}

5 0
2 years ago
Predict the bond angle in metgane using vsepr theory
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Bond Angle in the molecule of Methane according to the VSEPR theory is that it has a bond angle of 109.5 degrees with respect to the Carbon and the Hydrogen
6 0
3 years ago
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