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strojnjashka [21]
3 years ago
8

Balance the following chemical equation by providing the correct coefficients.

Chemistry
1 answer:
sukhopar [10]3 years ago
7 0

Answer:

2Na+2H2O→2NaOH+H2

Explanation:

I think this is it

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Calculate the % dissociation of 0.10 M solution of acetic acid (pKa = 4.75)
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Given :

Molarity of acetic acid solution, M = 0.10 M.

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To Find :

Percentage dissociation of 0.10 M solution of acetic acid.

Solution :

We know, pK_a = -log\  K_a

Taking antilog both side, we get :

K_a = 1.78\times 10^{-5}

Since, acetic acid has 1 hydrogen atom to loose , so it is a monoprotic acid.

Now, percentage dissociation of monoprotic acid is given by :

\alpha = \sqrt{\dfrac{K_a}{C}}\\\\\alpha =\sqrt{ \dfrac{1.78\times 10^{-5}}{0.1}}\\\\\alpha =  0.0133\times 100 = 1.33 \%

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