1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tekilochka [14]
3 years ago
6

If you have 1.1 moles of magnesium nitrate then how many grams is that

Chemistry
1 answer:
marysya [2.9K]3 years ago
3 0

Answer: 162.8 grams

Explanation:

Magnesium nitrate has a chemical formula of Mg(NO3)2.

Given that:

Number of moles of Mg(NO3)2 = 1.1 moles

Mass in grams of Mg(NO3)2 = ?

For Molar mass of Mg(NO3)2, use atomic mass of magnesium = 24g, nitrogen = 14g, oxygen = 16g

Mg(NO3)2 = 24g + (14g + 16gx3) x 2

= 24g + (14g + 48g) x 2

= 24g + (62g) x 2

= 24g + 124g

= 148g/mol

Now, apply the formula:

Number of moles = Mass in grams / molar mass

1.1 moles = Mass / 148g/mol

Mass = 1.1 moles x 148g/mol

Mass = 162.8 grams

Thus, there are 162.8 grams of magnesium nitrate.

You might be interested in
How many neutrons are in Lithium ​
Alik [6]

Answer:

They have 0-9 neurons

Explanation:

8 0
4 years ago
Ca (ClO) 2<br> Spell out the full name of the compound.
antoniya [11.8K]
Calcium hypochlorite
5 0
4 years ago
What is the charge on the phosphorus atom in the polyatomic ion: PO4-3
oee [108]

+5

Explanation:

  The given radical is                 PO₄³⁻

To solve this problem, we need to understand what oxidation number entails.

The extent of the oxidation of each atom is expressed by the oxidation number.

Here are some rules for assigning them:

  • Elements in an uncombined state or elements that combines with one another, their oxidation number is zero.
  • The charge on an ion is its oxidation number
  • In an neutral compound, algebraic sum of all the oxidation numbers of all atoms is zero.
  • In a radical, the algebraic sum of all the oxidation numbers of the ions is equal to the charge on them.

Oxygen is known to have an oxidation number of -2;

                       

                          PO₄³⁻

 P + 4(-2) = -3

 P -8 = -3

  P = -3 + 8 = +5

The charge on phosphorus is +5

learn more:

Oxidation number brainly.com/question/2086855

#learnwithbrainly

3 0
4 years ago
Why is the solar system often referred to as the sun’s family ?
snow_tiger [21]

Answer:the suns family is stars think about how many stars are in the sky there are billons and more billions

Explanation:

7 0
3 years ago
Read 2 more answers
A wave with low energy will also have high frequencies and long wavelength. short wavelengths and high frequencies. low frequenc
ch4aika [34]
A wave with low energy will also have long wavelengths and low frequencies.

The given in a single photon of a wave is given by Planck's equation:
E = hc/λ
and
E = hf

Where λ is the wavelength and f is the frequency of the photon. This means that energy is directly proportional to the frequency and inversely proportional to the wavelength. Thus, it is visible that photons with a lower frequency and a longer wavelength will have a lower energy.
8 0
3 years ago
Read 2 more answers
Other questions:
  • For the same mixture, under the same conditions described in problem 7, calculate keq for 2nh3 (g) n2 (g) + 3h2(g). how is the k
    5·1 answer
  • A weather map shows red semicircles on a line. What type of weather would one expect?
    8·2 answers
  • Write a balanced equation for its combustion reaction.
    6·1 answer
  • Which statement is true?
    5·2 answers
  • An organism's unique characteristics affect the individual's ability to survive in its environment. true or false
    13·2 answers
  • How many miles of NaOH will completely react with 10.0 mL of 1.0 M HCl?
    10·2 answers
  • Substance P is carbon.
    12·1 answer
  • WILL GIVE BRAINLEST
    9·2 answers
  • 1. Why is the timing of tides predictable?
    5·1 answer
  • Polymer formed from methylene diphenyl isocyanate
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!