The time required to get a total amount of $3,300.00 with compounded interest on a principal of $1,650.00 at an interest rate of 6.2% per year and compounded 12 times per year is 11.209 years. hence the answer is
A. 2001
<h3>Compound Interest Calculation</h3>
(about 11 years 3 months)
First, convert R as a percent to r as a decimal
r = R/100
r = 6.2/100
r = 0.062 per year,
Then, solve the equation for t
t = ln(A/P) / n[ln(1 + r/n)]
t = ln(3,300.00/1,650.00) / ( 12 × [ln(1 + 0.062/12)] )
t = ln(3,300.00/1,650.00) / ( 12 × [ln(1 + 0.0051666666666667)] )
t = 11.209 years
Learn more about Compound Interest here:
brainly.com/question/24924853
#SPJ1
Location because it was spent on most and the decades were filled with them
In
this question, this is an example of immediate corrective action.
<span>Immediate
corrective action is having a solution to the problem right away. This shows
that the manager provides action on the spot in the situation/problem. This
type of corrective action lacks sustainability and the duration of the solution
is not think through.</span>
Answer:
Jordan
Explanation:
Given that :
JORDAN :
Principal (P) = $100
Compound interest rate (r) = 3%
AMOUNT AFTER 3 YEARS:
A = P(1 + r/n)^nt
n = number of times interest is applied per period
t = time ; A = final amount
A = 100(1 + 0.03)^3
A = 100(1.03)^3
A = 100(1.092727)
A = $109.2727
JUSTIN :
Principal = $100
SIMPLE INTEREST interest rate = 3%
A = P(1 + rt)
A = 100(1 +(0.03 * 3))
A = 100(1 + 0.09)
A = 100(1.09)
A = 1.09 * 100
A = final amount after 3 years = $109
