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3 years ago

11

Maria cut a trapezoid out of a large piece of felt. Tha trapezoid has a height of 9 cm and bases of 6 cm and 11 cm. What is the

area of Marcia's felt trapezoid?

2 answers:

stiks02 [169]3 years ago

7 0

The area of Marcia's trapezoid felt is 76.5 sqaured centimeters

alex41 [277]3 years ago

4 0

Answer: 76.5 centimeters

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Step-by-step explanation:

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3 years ago

Use the rectangle hexagon with side length 10 meters to fill in the missing information

Vlada [557]

Answer:

$A_h=150\sqrt{3}\ m^2$

Step-by-step explanation:

<u>Regular Hexagon</u>

For the explanation of the answer, please refer to the image below. Let's analyze the triangle shown inside of the hexagon. It's a right triangle with sides x,y, and z.

We know that x is half the length of the side length of the hexagon. Thus

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Now we have $\theta$ , the height of the triangle y is easily found by

$\displaystyle tan30^o=\frac{x}{y}$

Solving for y

$\displaystyle y=\frac{x}{tan30^o}=\frac{5}{ \frac{1} {\sqrt{3} }}=5\sqrt{3}$

The value of z can be found by using

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$\displaystyle z=\frac{x}{sin30^o}=\frac{5}{\frac{1}{2}}=10$

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$\displaystyle A_t=\frac{xy}{2}=\frac{5\cdot 5\sqrt{3}}{2}=\frac{25\sqrt{3}}{2}$

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$\displaystyle A_h=12\cdot A_t=12\cdot \frac{25\sqrt{3}}{2}=150\sqrt{3}$

$\boxed{A_h=150\sqrt{3}\ m^2}$

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