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4 years ago

What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (-2,4)?

Mathematics

1 answer:

pav-90 [236]4 years ago

7 0

Answer:

y=-5/2x-1

Step-by-step explanation:

change the equation to slope intercept form

y=-5/2x+6

graph the point (-2, 4)

use the slope of the equation to find the y intercept

y intercept = -1

write equation of the parallel line using the same slope of the first line

-5/2x

and the y intercept of the new parallel line -1

y=-5/2x-1

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Find the slope-intercept form of the equation of the line through the point (0, -4) and (1, 0).

Arisa [49]

Answer:

The Slope Intercept form of the equation through the point (0, -4) and

(1, 0) is y = 4 x - 1

Step-by-step explanation:

Here, the given points are A (0,-4) and B(1,0)

Now, slope of the equation with points (a,b) and (c,d) is given as

$m = \frac{d - b}{c -a}$

So, here the slope of the line AB is given as:

$m = \frac{0 - (-4)}{1-0} = \frac{4}{1} = 4$

⇒ m = 4

Now, by POINT SLOPE form:

The equation with slope m and point (x0 , y0) is represented as :

(y-y0) = m (x-x0)

⇒ The equation of AB is of the form with point (1,0) is

y - 0 = 4 (x -1)

or, y = 4 x - 1

Also, the SLOPE INTERCEPT form of an equation is of the form

y = m x + C ; m = slope and C = y -intercept

Hence, the slope intercept form of the equation through the point (0, -4) and (1, 0) is y = 4 x - 1

4 0

4 years ago

Find the distance from P to l.

ki77a [65]

$Equation\ of\ a\ line\ from\ 2\ points (x_1;\ y_1);\ (x_2;\ y_2):\\\\y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\(-4;\ 2)\ and\ (3;-5)\\subtitute:\\\\y-2=\dfrac{-5-2}{3-(-4)}\cdot(x-(-4))\\\\y-2=\dfrac{-7}{7}\cdot(x+4)\\\\y-2=-(x+4)\\\\y-2=-x-4\ \ \ |add\ x\ and\ 4\ to\ both\ sides\\\\x+y+2=0\\-------------------\\$

$Point-line\ distance\\l:Ax+By+C=0;\ (x_0;\ y_0)\\\\d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}\\\\x+y+2=0\to A=1;\ B=1;\ C=2\\(1;\ 2)\to x_0=1;\ y_0=2\\subtitute\\\\d=\dfrac{|1\cdot1+1\cdot2+2|}{\sqrt{1^2+1^2}}=\dfrac{|1+2+2|}{\sqrt2}=\dfrac{|5|}{\sqrt2}=\dfrac{5}{\sqrt2}=\dfrac{5\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\\\\=\boxed{\dfrac{5\sqrt2}{2}}$

4 0

4 years ago

Geometry help please!!!

julia-pushkina [17]

Before we begin, let's identify what kind of angles these are and are they related in any way?

These angles are both acute and they are both corresponding angles.
Corresponding angles are equal to each other, and we can use this fact to our advantage.

Since they are equal to each other, we can set the equations of 1 and 2 equal to each other. Like so,

1 = 2
83 - 2x = 92 - 3x

Now, we can solve for X by isolating it on one side.

83 - 2x = 92 - 3x

Add 3x to each side: (This basically moves the X on the right side to the left.)
83 - 2x + 3x = 92 - 3x + 3x
83 + x = 92

Subtract 83 on each side to isolate the X.
83 + x - 83 = 92 - 83
x = 92 - 83
x = 9

Therefore, X equals 9. To check our work, we can substitute X for 9.
83 - 2(9) = 92 - 3(9)
83 - 18 = 92 - 27
65 = 65 -
TRUE

So to conclude, Angle 1 is 65 degrees, Angle 2 is 65 degrees, and X equals 9.

Hope I could help you out!
If my answer is incorrect, or I provided an answer you were not looking for, please let me know. However, if my answer is explained well and correct, please consider marking my answer as Brainliest! :)

Have a good one.
God bless!

7 0

3 years ago

Someone please help asap, I will mark as brainliest. Thank you!!

defon

Answer:

the answer is c go ahead and click it

Step-by-step explanation:

8 0

2 years ago

What is 1+1? I am very confused, is it 1, 0, or 3?

Yuri [45]

Answer:

1 + 1 = 2, if you are doing multiplication then it is 1 x 1 = 1

Step-by-step explanation:

8 0

3 years ago