Question

PLEASE HELP!!!!!

Answer 1

Answer:

  A, D, E (probably preferred)

  B, C, F (also true)

Step-by-step explanation:

"This situation" problems are almost always ambiguous. The first problem is to figure out what it is about "this situation" that you want to model.

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If we want to model concession stand revenue in a general way, then statements B, C, and F could represent "this situation." No specific values can be determined from this model.

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More likely, we want to model the details of sales and revenue, so we want to know the exact numbers of water bottles and hamburgers that were sold. For "this situation," we can assign variables to the numbers of items of each type, and write equations for the total number of items and for the revenue their sales generates. Appropriate statements about this interpretation of the problem are those of A, D, and E:

  A: x could represent bottles sold

  D: y could represent hamburgers sold

  E: The system of equations could be 2.50x +5.50y = 1325; x +y = 350.

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The solution to the last model is 200 bottles were sold for revenue of $500, and 150 hamburgers were sold for revenue of $825.

Answer 2

Answer:

A-The variable x could represent the number of bottles of water sold.

D-The variable y could represent the number of hamburgers sold.

E-The system of equations that could represent the concession sales is

2.50x + 5.50y = 1,325

x+y=350

Step-by-step explanation:

When doing a system of equations you need variables and constants, in this case it´s easy to know what are the constants, since they are given directly to you by the problem, the constan 1 is the cost of the bottled water, the cost of each hamburger, the number of items sold and the total sum of the sells.

The only variables that we have are the number of items sold, we are going to express them with X and Y, the cost of the number of bottles of water sold will be expressed with the letter X and the number of hamburgers sold will be expressed by the letter Y.