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iragen [17]
3 years ago
15

If you want to copy a file from one folder to another , what would you do?

Computers and Technology
1 answer:
Talja [164]3 years ago
4 0
Cd /path/to/source/directory
cp fileName /path/to/destination/directory
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As a highly flexible structure, __________ can be quickly configured to adapt as required due to changes.
tresset_1 [31]

As a highly flexible structure, a <u>matrix organization</u> can be quickly configured to adapt as required due to changes.

<h3>What is a matrix organizational structure?</h3>

A matrix organizational structure can be defined as a type of work structure where reporting relationships between employees and the top executive (employers) are set up as a matrix rather than the conventional hierarchy approach, which makes it highly flexible and adaptable to subsequent changes.

<h3>The types of matrix organizational structure.</h3>

In business management, there are three types of matrix organizational structure and these include:

  • Weak matrix structure.
  • Balanced matrix structure.
  • Strong matrix structure.

Read more on matrix organization here: brainly.com/question/7437866

7 0
3 years ago
It is not free to manage the settings of your wiki (true or false)​
jek_recluse [69]

Answer:

shuush

Explanation:

u r a shmaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaak

5 0
3 years ago
I want an A! Write a pseudocode algorithm that asks the user for their grades in CSE 1321, along with their attendance, then cal
Vsevolod [243]

Answer:

The Java pseudocode and the Java code itself are given for better understanding

Explanation:

<u>Java pseudocode</u>

  1. preAvg(int test[], int qgrade):
  2. sum := 0
  3. for each testi in test:
  4. sum := sum + testi
  5. sum := sum + qgrade
  6. return sum / 5
  7. additional(int at):
  8. res = (at * 1.5) / 30
  9. return res
  10. total = preAvg(test, qgrade) + additional(at)

<u>Java code</u>

import java.util.Scanner;

public class CSE1322 {

  public static void main(String[] args) {

     

      Scanner scanner=new Scanner(System.in);

     

      int test[] = new int[4];

     

      for(int i=1;i<=4;i++){

          System.out.println("Enter your result for test"+i+": ");

          test[i-1] = scanner.nextInt();

      }

     

      System.out.println("Enter the average quiz grade: ");

      int qgrade = scanner.nextInt();

     

      System.out.println("Enter the classes you attended(out of 30): ");

      int at = scanner.nextInt();

     

      double avg = preAvg(test,qgrade);

      System.out.println("Your average before attendance is: "+avg);

     

      double add = additional(at);

      System.out.println("You receive an additional "+add+" points for attendance");

     

      double total = avg + add;

     

      System.out.println("Final grade is : "+total);

     

  }

  private static double additional(int at) {

      double res = ((double)at * 1.5)/30.0;

      return res;

  }

  private static double preAvg(int[] test, int qgrade) {

      double sum = 0;

     

      for(int i=0;i<4;i++) sum += test[i];

     

      sum += qgrade;

     

      return sum/5;

  }

}

4 0
4 years ago
find_cow(name, cows) Given a name and a Python list of Cow objects, return the Cow object with the specified name. If no such Co
nadya68 [22]

Using the computational knowledge in python it is possible to write a code that Given a name and a Python list of Cow objects

<h3>Writting the code in python:</h3>

<em>def load_cows(filename):</em>

<em>      cow_dict = dict()</em>

<em>    f = open(filename, 'r')</em>

<em> </em>

<em>    for line in f:</em>

<em>        line_data = line.split(',')</em>

<em>        cow_dict[line_data[0]] = int(line_data[1])</em>

<em>    return cow_dict</em>

<em>def greedy_cow_transport(cows, limit=10):</em>

<em>       trips = []</em>

<em>    cowsCopy = cows.copy()</em>

<em>    sortedCows = sorted(cowsCopy.items(), key=lambda x: x[1], reverse = True)</em>

<em>    while sum(cowsCopy.values()) > 0:</em>

<em>        ship = []</em>

<em>        total = 0</em>

<em>        for cow, value in sortedCows:</em>

<em>            if cowsCopy[cow] != 0 and value + total <= limit:</em>

<em>                ship.append(cow)</em>

<em>                total += value</em>

<em>                cowsCopy[cow] = 0</em>

<em>        trips.append(ship)</em>

<em>    return trips</em>

<em>def brute_force_cow_transport(cows,limit=10):</em>

<em>     trips = []</em>

<em>     possibilities = []</em>

<em>    for i in power_list:</em>

<em>        ship = []</em>

<em>        for j in i:</em>

<em>            ship_weights = []</em>

<em>            for k in j:</em>

<em>                ship_weights.append(cows[k])</em>

<em>                #print(ship_weights)</em>

<em>            ship.append(sum(ship_weights))</em>

<em>            #print(ship)</em>

<em>        if all(d <= limit for d in ship):</em>

<em>            possibilities.append(i)</em>

<em>      pruned_possibilities = []</em>

<em>    for k in possibilities:</em>

<em>        if k not in pruned_possibilities:</em>

<em>            pruned_possibilities.append(k)</em>

<em>    # now find the minimum list length:</em>

<em>    min_list_len = min(map(len, pruned_possibilities))</em>

<em>    for l in pruned_possibilities:</em>

<em>        if len(l) == min_list_len:</em>

<em>            return l</em>

<em>       </em>

<em>def compare_cow_transport_algorithms():</em>

<em>       greedy_start = time.time()</em>

<em>    greedy_results = greedy_cow_transport(cows, limit = 10)</em>

<em>    greedy_end = time.time()</em>

<em>    print('Greedy Algorithm time:', greedy_end -greedy_start)</em>

<em>    brute_force_start = time.time()</em>

<em>    brute_force_results = brute_force_cow_transport(cows, limit = 10)</em>

<em>    brute_force_end = time.time()</em>

<em>    print('Brute force time:', brute_force_end - brute_force_start)</em>

<em>    print('Greedy Algorithm results:', greedy_results)</em>

<em>    print('Number of trips returned by Greedy Algorithm:', len(greedy_results))</em>

<em>    print('Brute Force Algorithm results:', brute_force_results)</em>

<em>    print('Number of trips returned by Brute Force Algorithm:', len(brute_force_results))</em>

   

See more about python at brainly.com/question/13437928

#SPJ1

4 0
2 years ago
Which feature of virtualisation helps increase the IT productivity of a business
PIT_PIT [208]

Answer:

Add, remove, organize and reorder commands on the Quick Access Toolbar. ... The Quick Access Toolbar is a customizable toolbar that contains a set of ... The only way to increase the size of the buttons is to lower the screen resolution you use. ... However, you can Customize the ribbon in Office to personalize the ribbon ...

Explanation:

because

8 0
4 years ago
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