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yawa3891 [41]
3 years ago
15

The concentration of pb2+ in a commercially available standard solution is 1.00 mg/ml. what volume of this solution should be di

luted to 6.0×102 ml to produce a solution in which the concentration of pb2+ is 0.054 mg/l?
Chemistry
1 answer:
Vanyuwa [196]3 years ago
3 0
<span>The concentration of pb2+ = 1.00mg/ml Diluted Solution is 6.0 x 102 ml = 612 ml Volume of the concentration of pb2+ is 0.054 mg/l is v (vL)(1.00mg/ml) = (.612L)(0.054mg/l) Volume = 0.033048L Volume of the concentration of pb2+ is 0.054 mg/l = 33.048 ml.</span>
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What description best describes both mirrors and lenses?
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Mirrors reflect light and lenses refract light.
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Molecules that are optically active due to the tetrahedral arrangement of bonds around the carbon atom are often referred to as
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3 years ago
Which of the following helps explain how a rainbow of colors can form when sunlight passes through a prism?
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B . seems the most logical tbh
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3 years ago
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Sodium chloride can be produced from reacting sodium metal with chlorine gas. Carly reacts 2.6 g of sodium with 5.0 g of chlorin
Artemon [7]

Answer:

87.75%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2Na + Cl₂ —> 2NaCl

Next, we shall determine the masses of Na and Cl₂ that reacted and the mass of NaCl produced from the balanced equation. This can be obtained as follow:

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g

Molar mass of Cl₂ = 2 × 35. 5 = 71 g/mol

Mass of Cl₂ from the balanced equation = 1 × 71 = 71 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g

Summary:

From the balanced equation above,

46 g of Na reacted with 71 g of Cl₂ to produce 117 g of NaCl.

Next, we shall determine the limiting reactant.

This can be obtained as follow:

From the balanced equation above,

46 g of Na reacted with 71 g of Cl₂.

Therefore, 2.6 g of Na will react with = (2.6 × 71)/46 = 4.01 g of Cl₂.

From the calculations made above, we can see that only 4.01 g of Cl₂ at of 5 g given in question reacted completely with 2.6 g of Na. Therefore, Na is the limiting reactant and Cl₂ is the excess reactant.

Next, we shall determine the theoretical yield of NaCl. The limiting reactant will be used to obtain the theoretical yield since all of it is consumed in the reaction.

The limiting reactant is Na and the theoretical yield of NaCl can be obtained as follow:

From the balanced equation above,

46 g of Na reacted to produce 117 g of NaCl.

Therefore, 2.6 g of Na will react to produce = (2.6 × 117)/46 = 6.61 g of NaCl.

Thus the theoretical yield of NaCl is 6.61 g

Finally, we shall determine the percentage yield of NaCl. This can be obtained as follow:

Actual yield of NaCl = 5.8 g

Theoretical yield of NaCl = 6.61 g

Percentage yield =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 5.8/6.61 ×100

Percentage yield of NaCl = 87.75%

7 0
3 years ago
What occurs in order to break the bond in a Cl, molecule?
Ann [662]

Answer:

Explanation:

The attachment or (Bond) that resolves around the atoms of CI2 which is a covalent bond, yet energy is needed to destroy the bond and when new bonds are produced, energy is unleashed while the bond's development makes the molecule equilibrated. In short terms to basically break this bond energy is required and another terms energy is occupied and is the conclusion to your question (I tried my best) Energy is absorbed which is the result of what occurs.

8 0
3 years ago
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