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Goryan [66]
3 years ago
14

Please help I will give you the brainiest.

Chemistry
2 answers:
Scilla [17]3 years ago
6 0

Answer:c mark brainliest

Explanation:

fiasKO [112]3 years ago
3 0

The answer is  D).

Inflate one balloon to a large  volume and another ballon to a small vomume. measure the temperature of the air rakeased form both balloons

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The molar mass of an element is the mass of one
allochka39001 [22]

Answer:

  • <em>The molar mass of an element is the mass of </em><u>one mole of atoms of the element.</u>

Explanation:

<em>The molar mass of an element </em>is its atomic mass, i.e.  the mass in grams of one mole of atoms of the element.

Remember 1 mol is approximately 6.022 × 10²³.

So, 1 mol of atoms is 6.022 × 10²³ atoms.

The molar mass is an average: it is the weighted average mass of the natural isotopes of the element, taking into account their relative abundance.

For example, the molar mass or atomic mass of carbon is 12,0107 g/mol, instead of 12.0000, becasue carbon exists in several forms (isotopes), and so the weighted average is not a whole number.

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3 years ago
The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichl
nevsk [136]

Complete Question

A student is extracting caffeine from water with dichloromethane. The K value is 4.6. If the student starts with a total of 40 mg of caffeine in 2 mL of water and extracts once with 6 mL of dichloromethane

The experiment above is repeated, but instead of extracting once with 6 mL the extraction is done three times with 2 mL of dichloromethane each time. How much caffeine will be in each dichloromethane extract?

Answer:

The mass of  caffeine extracted is  P =  39.8 \ mg

Explanation:

From the question above  we are told that

    The  K value is  K =  4.6

     The  mass of the caffeine is  m  = 40 mg

      The  volume of water is  V  = 2 mL

      The volume  of caffeine is  v_c =  2 mL

     The number of times the extraction was done is  n =  3

Generally the mass of  caffeine that will be  extracted is  

           P =  m  *  [\frac{V}{K *  v_c + V} ]^3

substituting values  

           P =  40   *  [\frac{2}{4.6 *  2 + 2} ]^3

           P =  39.8 \ mg

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