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valentina_108 [34]
3 years ago
12

Which of the following elements possesses the fewest valence electrons? bismuth boron barium bromine

Chemistry
2 answers:
denis-greek [22]3 years ago
6 0

Answer:

The correct answer is barium.

Explanation:

Valence electrons are the electrons present in the valence shell of an atom of an element.

Bismuth has atomic number of 83.

[Bi]=[Xe]6s^26p^3

Number of valence electron = 5

Boron has atomic number of 5.

[B]=[He]2s^22p^1

Number of valence electron = 3

Barium has atomic number of 56.

[Ba]=[Xe]6s^2

Number of valence electron = 2

Bromine has atomic number of 35.

[Br]=[Ar]4s^24p^5

Number of valence electron = 7

Barium is one of the element in the given options which possesses fewest number of valence electrons

scZoUnD [109]3 years ago
4 0
Bismuth has 5 valence electrons
Boron has 3 valence electrons 
Barium has 2 valence electrons
Bromine has 7 valence electrons

So therefore, the correct answer would be Barium.
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­­2K + 2HBr → 2 KBr + H2
Inessa [10]

Answer:

\large \boxed{\text{0.0503 g}}

Explanation:

The limiting reactant is the reactant that gives the smaller amount of product.

Assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r:   39.10    80.41                2.016  

            2K  +  2HBr ⟶ 2KBr + H₂

m/g:     5.5      4.04

a) Limiting reactant

(i) Calculate the moles of each reactant  

\text{Moles of K} = \text{5.5 g} \times \dfrac{\text{1 mol}}{\text{31.10 g}} = \text{0.141 mol K}\\\\\text{Moles of HBr} = \text{4.04 g} \times \dfrac{\text{1 mol}}{\text{80.91 g}} = \text{0.049 93 mol HBr}

(ii) Calculate the moles of H₂ we can obtain from each reactant.

From K:  

The molar ratio of H₂:K is 1:2.

\text{Moles of H}_{2} = \text{0.141 mol K} \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol K}} = \text{0.0703 mol H}_{2}

From HBr:  

The molar ratio of H₂:HBr is 3:2.  

\text{Moles of H}_{2} = \text{0.049.93 mol HBr } \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol HBr}} = \text{0.024 97 mol H}_{2}

(iii) Identify the limiting reactant

HBr is the limiting reactant because it gives the smaller amount of NH₃.

b) Excess reactant

The excess reactant is K.

c) Mass of H₂

\text{Mass of H}_{2} = \text{0.024 97 mol H}_{2} \times \dfrac{\text{2.016 g H}_{2}}{\text{1 mol H}_{2}} = \textbf{0.0503 g H}_{2}\\ \text{The mass of hydrogen is $\large \boxed{\textbf{0.0503 g}}$ }

3 0
3 years ago
Please help. it’s my last question.
ale4655 [162]
<h3>Further explanation </h3>

Given

Atomic symbol

Required

Atomic composition

Solution

Atomic number = number of protons = number of electrons

Mass Number (A) is the sum of protons and neutrons

Number of protons and Number of Neutrons  in nucleus

Number of electrons in the shell

From the picture:

protons = 3

neutrons = 4

electrons = 3

atomic number = protons = electrons = 3

mass number = protons + neutrons = 3+4 = 7

4 0
3 years ago
What is formed when a carboxylic acid and an amine combine? Give an example of the type of polymer that is formed by this reacti
Vesna [10]

Answer:

The reaction between amines and carboxylic acids to form amides is biologically important. It is through this reaction that amino acids (molecules containing both amine and carboxylic acid substituents) link together in a polymer to form proteins.

6 0
3 years ago
What can scientists learn by studying fossils? I HAVE ANSWER
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Answer:

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Can you describe the situations when Greek prefixes are used?
Black_prince [1.1K]

Answer:

Here's what I get  

Explanation:

At the introductory level of chemistry, I can think of only two situations when you use Greek prefixes.

They indicate the number of atoms or groups in a molecule when you are naming a compound.

1. Binary covalent compounds

For example, P₂S₅ is diphosphorus pentasulfide.

2. Hydrates

For example, Na₂SO₄·10H₂O is sodium sulfate decahydrate.

7 0
3 years ago
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