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beks73 [17]
3 years ago
15

Carbon dioxide and water react to form bicarbonate ion and hydronium ion. Hyperventilation (rapid breathing) causes more carbon

dioxide to be exhaled than normal. How will hyperventilation affect the pH of blood?
this is about a unit on shifting equilibrium and the common-ion effect so try to connect the explanation to those ideas please!
Chemistry
1 answer:
Juliette [100K]3 years ago
4 0
Hyperventilation<span> will blow off carbon dioxide which reduces the alkaline component of the </span>blood<span>, resulting in acidosis and a lower </span>blood pH<span>. (See Andromeda Strain). This is why re-breathing into a bag to increase carbon dioxide in your </span>blood will make you feel less faint. Basically <span>It increases the pH ... you can look at CO2 as an acid ... and when reduced ... alkalinization of the pH occurs</span> 
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If one serving of a packaged frozen dinner contains 5.2 grams of saturated fat and the maximum recommended daily intake of satur
den301095 [7]

Answer:

The percentage of the daily value for saturated fat provided by one package of this food is 26.0%

Explanation:

It has been given from the preceding statement that one package of the dinner provides 5.2g out of the 20 grams recommended for daily need. This is 5.2/20 x 100 given 26.0% of the daily neded value will be provided by a plate or package of the dinner.

7 0
3 years ago
I want someone he is good in chemistry
Over [174]

Answer:

<h2>.I can help you.....</h2>

Explanation:

<h2>am good at </h2>

moles

bonding

balancing equations

and set ups

8 0
3 years ago
A civil engineering student is considering buying an electric car. However, the conscious student wants to make sure her carbon
svetlana [45]

Answer:

\text{An gasoline-powered vehicle has }\\\boxed{\text{five times the carbon footprint}}\text{ of an electric vehicle.}

Explanation:

1. Miles travelled in an average month  

\text{Miles} = \text{1 mo} \times \dfrac{\text{52 wk}}{\text{12 mo}} \times \dfrac{\text{5 da}}{\text{1 wk}} \times \dfrac{\text{16 mi}}{\text{1 da}} = \text{347 mi}

2. Using a gasoline powered vehicle  

(a) Moles of heptane used  

n = \text{347 mi} \times \dfrac{\text{1 gal}}{\text{36.5 mi}}\times \dfrac{\text{3.785 L}}{\text{1 gal}} \times \dfrac{\text{679.5 g}}{\text{1L}} \times \dfrac{ \text{1 mol}}{\text{100.20 g}}= \text{244 mol}

(b) Equation for combustion  

C₇H₁₆ + O₂ ⟶ 7CO₂ + 8H₂O  

(c) Moles of CO₂ formed  

n = \text{244 mol heptane} \times \dfrac{\text{7 mol CO$_{2}$}}{\text{1 mol heptane}} = \text{1710 mol CO$_{2}$}

(d) Volume of CO₂ formed  

At 20 °C and 1 atm, the molar volume of a gas is 24.0 L.  

V = \text{1710 mol } \times \dfrac{\text{24.0 L}}{\text{1 mol}} \times \dfrac{\text{1 gal}}{\text{3.785 L}} = \textbf{10 800 gal}

3. Using an electric vehicle  

(a) Theoretical energy used  

\text{Theor. Energy} = \text{347 mi} \times \dfrac{\text{1 kWh}}{\text{5.2 mi}} = \text{66.7 kWh theor.}

(b) Actual energy used  

The power station is only 85 % efficient.  

\text{Actual energy used} = \text{66.7 kWh theor.} \times \dfrac{\text{100 kWh actual}}{\text{ 85 kWh theor.}}\times \dfrac{\text{3600 kJ}}{\text{1 kWh}}\\\\ = 2.82\times 10^{5} \text{ kJ}\

(c) Combustion of CH₄

CH₄ + 2O₂ ⟶ CO₂ +2 H₂O

(d) Equivalent volume of CO₂

The heat of combustion of methane is -802.3 kJ·mol⁻¹  

V= 2.82\times 10^{5}\text{ kJ} \times \dfrac{\text{1 mol methane}}{\text{802.3 kJ}} \times \dfrac{\text{1 mol CO$_{2}$} }{\text{1 mol methane}} \times \dfrac{ \text{24.0 L}}{ \text{1 mol CO$_{2}$}}\\\\ \times \dfrac{\text{1 gal}}{\text{3.875 L}} = \textbf{2180 gal}

4. Comparison  

\dfrac{V_{\text{gasoline}}}{V_{\text{electric}}} = \dfrac{10800}{2180} = 5.0\\\\ \text{An gasoline-powered vehicle has }\\ \boxed{\textbf{ five times the carbon footprint}}\text{ of an electric vehicle.}

6 0
3 years ago
What is the pH of a solution with an H3O+ concentration of 5.67 x 10-4 M?
Valentin [98]

Answer:

<h2>3.25 </h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ { H_3O}^{+}]

From the question we have

ph =  -  log(5.67 \times  {10}^{ - 4} )  \\  = 3.2464

We have the final answer as

<h3>3.25 </h3>

Hope this helps you

3 0
2 years ago
I NEED HELP PLEASE !!!!
inysia [295]

Answer:

over 10 weeks the plant will grow 24 time longer than the the same hieght of the plant and the plant age will become 45 and so the plant is very much give hey man is my answer corecct

Explanation:

3 0
3 years ago
Read 2 more answers
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