Water can only dissolve inorganic compounds is false
Answer:
The unknown element is Sb
Explanation:
The first thing we must note is that the unknown element must be a member of group 15 in the periodic table. This is clear from the fact that the two oxides formed are X2O3 and X2O5. This implies that the unknown element X must have a valency of 3 or 5. This corresponds to our knowledge that the outermost electron configuration of group 15 elements is ns2np3. Hence, group fifteen elements can have a valency of 3 or 5.
The electronic configuration of antimony is; [Kr]4d10 5s2 5p3. This implies that the atom is paramagnetic since there are three unpaired 5p electrons. The oxides of antimony are known to be amphoteric. An ampohoteric oxide reacts with both acid and base, hence the answer.
Answer:
2 and 3 because there are the protons and neutrons which have a greater mass than the electrons which are found in the locations 1 and 4. The atom contains a nucleus, which is made from protons and neutrons, and electrons which are found around the nucleus. The mass of the atoms is concentrated in the very tiny space represented by the nucleus. Of course the electrons have a mass too, but is very small compared to the protons and neutrons, and we usually neglect its mass.
Explanation:
The question involves converting from one unit (Kilometres) to another unit (Astronomical unit)
The relationship between both units is given as;
1 Km = 6.68459e-9 Au
Kulper belt
6.5 billion km = 6.5e9 Km
1 Km = 6.68459e-9 Au
6.5e9 Km = x
Solving for x;
x = 43.45 Au
Alpha Centauri
44 trillion km = 4.4e13
1 Km = 6.68459e-9 Au
4.4e13 km = x
Solving for x;
x = 294121.83 Au
Answer:
0.900 V
Explanation:
Oxidation half cell;
2Al(s) -----> 2Al^3+(aq) + 6e
Reduction half equation;
3Zn^2+(aq) + 6e ----> 3Zn(s)
E°anode = -1.66V
E°cathode= -0.76 V
E°cell= E°cathode - E°anode
E°cell= -0.76-(-1.66)
E°cell= 0.900 V
