What happens in this circuit if one of the light bulbs burns out?

Oliga [24]

Answer:the energy required by an atom to lose or gain electron (e-) to be able to form ions.either cation or anion.

Explanation:

to lose or gain e- an atom has to donate or receive e- to to this it requires the more easily it can lose an electron the more electro positive it is and the more easily it gains electron the more electro negative it is.

4 0

3 years ago

4. If the earth were to heat up by 3 degrees, approximately how much would the sea level rise?

Ksju [112]

The sea level would rise by some 50 meters.

Explanation:

If the earth's temperature increases by 3 degrees the north and south pole would experience the ice melt at high speed.

The life will get difficult on the plains.

The extinction of some species will happen.

The sea level would rise by 50 meters. The increased sea level will cause depletion of habitat from plants and animals.

The floods will occur, land erosion, soil for agriculture land will get contaminated with the salt.

8 0

3 years ago

A 50.0 mL solution of 0.141 M KOH is titrated with 0.282 M HCl . Calculate the pH of the solution after the addition of each of

Kobotan [32]

Answer:

pH =1 2.84

Explanation:

First we have to start with the reaction between HCl and KOH:

$HCl~+~KOH->~H_2O~+~KCl$

Now for example, we can use a volume of 10 mL of HCl. So, we can calculate the moles using the molarity equation:

$M=\frac{mol}{L}$

We know that $10mL=0.01L$ and we have the concentration of the HCl $0.282M$ , when we plug the values into the equation we got:

$0.282M=\frac{mol}{0.01L}$

$mol=0.282*0.01$

$mol=0.00282$

We can do the same for the KOH values ( $50mL=0.05L$ and $0.141M$ ).

$0.141M=\frac{mol}{0.05L}$

$mol=0.141*0.05$

$mol=0.00705$

So, we have so far 0.00282 mol of HCl and 0.00705 mol of KOH. If we check the reaction we have a molar ratio 1:1, therefore if we have 0.00282 mol of HCl we will need 0.00282 mol of KOH, so we will have an excess of KOH. This excess can be calculated if we substract the amount of moles:

$0.00705-0.00282=0.00423mol~of~KOH$

Now, if we want to calculate the pH value we will need a concentration, in this case KOH is in excess, so we have to calculate the concentration of KOH. For this, we already have the moles of KOH that remains left, now we need the total volume:

$Total~volume=50mL+10mL=60mL$