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krek1111 [17]
2 years ago
6

HELP ME PLSSSSS THIS TEST IS TIMED!!!! Write a conclusion statement that addresses the following questions: • How did your exper

imental absolute zero value compare to the accepted value? • Does your data support or fail to support your hypothesis (include examples)? • Discuss any possible sources of error that could have impacted the results of this lab. • How do you think the investigation can be explored further?
Chemistry
1 answer:
SVETLANKA909090 [29]2 years ago
4 0

Although the data for the experiment was not provided, we can offer a generalized answer in that when performing an experiment to achieve absolute zero temperatures, the value will never match the exact value.

<h3 /><h3>What is absolute zero?</h3>

Absolute zero is the lower limit of temperature. It is considered the coldest possible temperature that can exist. However, any attempt to reach this temperature in a controlled environment has failed, <u>scientists do not think it is possible to recreate this </u><u>temperature</u><u>. </u>

Therefore, we can confirm that the value of the absolute zero experiments did not match the accepted value. If the hypothesis was that it would be difficult or impossible to achieve, then the data would support the hypothesis, otherwise, it would fail to do so.

In summary, absolute zero is a temperature that cannot be recreated in a lab, so the value in this experiment does not match the accepted value and there is <u>no further exploration </u>to be done on this matter.

To learn more about absolute zero visit:

brainly.com/question/79835?referrer=searchResults

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what volume of ethylene gas at 293K and 102kPa must be compressed to yield 295m3 of ethylene gas at 808kPa and 585K​
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<h3>Answer:</h3>

1170.43 m³

<h3>Explanation:</h3>

<u>We are given;</u>

  • Initial pressure, P1 as 808 kPa
  • Initial temperature, T1 as 585 K
  • Initial volume, V1 as 295 m³
  • New pressure, P2 as 102 kPa
  • New temperature, T2 as 293 K

We are required to find the new volume;

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  • According to the gas law;  \frac{P1V1}{T1}=\frac{P2V2}{T2}
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V2=\frac{P1V1T2}{P2T1}

V2=\frac{(808 kPa)(295)(293K)}{(102 kPa)(585K)}

V2=1170.43

Therefore, the volume is 1170.43 m³

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An object has a mass of 2800g and a volume of 3cm3. What is its density?<br>​
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933.33 g/cm³

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