The given formula for heat, Q=mc(Tf-Ti), is the best way to solve such problems with changes in temperature. It can be said that m is the mass of the substance. C is the specific heat of the substance. The term (Tf-Ti) is the change in temperature.
Q = mc(Tf-Ti) = 480g(0.96 J/g-C)(234-22) = 97689.6 Joules of heat
Answer: E
Explanation:
The lattice energy is the energy change when one mole of a crystal is formed from its components ions in its gaseous sate
Therefore lattice energy = heat of Sublimation+ ionization energy +electron affinity-(heat of formation)
Therefore lattice Energy = 109 +495 -328 +570.
Lattice energy = --923kjmol-1
Answer:
2Al(NO3)3 + 3H2SO4 → Al2(SO4)3 + 6HNO3
Explanation:
i just looked up how to balance it, i dont really know how to balance it exactly
I think the answer is true if so i hope it helps
Answer:
See Explanation
Explanation:
Ionization energy refers to the energy required to remove an electron from an atom. Metals have lower ionization energy than non metals since ionization energy increases across a period.
One thing that we must have in mind is that it takes much more energy to remove an electron from an inner filled shell than it takes to remove an electron from an outermost incompletely filled shell.
Now let us consider the case of magnesium which has two outermost electrons. Between IE2 and IE3 we have now moved to an inner filled shell(IE3 refers to removal of electrons from the inner second shell) and a lot of energy is required to remove an electron from this inner filled shell, hence the jump.
For aluminium having three outermost electrons, there is a jump between IE3 and IE4 because IE4 deals with electron removal from a second inner filled shell and a lot of energy is involved in the process hence the jump.
Hence a jump occurs each time electrons are removed from an inner filled shell.
