At STP, one mole of gas occupies 22.4 L of space. Assuming the conditions conform to STP
volume CO2 = 0.5 mol * 22.4 L/1 mol
= 11.2 L
= 10 L
The answer with 1 significant figure is 10 L of CO2
Answer:
3.78 x 10^24
Explanation:
I mol = 6.02X10^23 atoms
So,
I did not round the last number
the full answer was, 3.78056 x 10^24
Answer:
36.23 %
Explanation:
Let's <em>assume we have 1 mol of FeCl₂ · 4H₂O</em>. In that case we would have:
- 1 mol of FeCl₂, weighing 126.75 g (that's the molar mass of FeCl₂), and
- 4 moles of H₂O, weighing (4 * 18 g/mol) 72 g.
Now we can <u>calculate the percent by mass of water</u>:
- % mass = mass of water / total mass * 100%
- % mass =
* 100% = 36.23 %
Answer:
O.
Explanation:
- The element which is oxidized is the element that losses electrons and its oxidation state be more positive.
- The element which is reduced is the element that gain electrons and its oxidation state be more negative.
<em> O goes from 0 to -2, so, it is the element that is reduced.</em>