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Anna71 [15]
2 years ago
10

The reaction N2O4↽−−⇀2NO2 is allowed to reach equilibrium in a chloroform solution at 25 ∘C . The equilibrium concentr

ations are 0.371 mol/L N2O4 and 2.04 mol/L NO2 . Calculate the equilibrium constant, Kc , for this reaction.
Chemistry
1 answer:
Harman [31]2 years ago
4 0

The reaction N2O4↽−−⇀2NO2 is allowed to reach equilibrium in a chloroform solution at 25 ∘C . The equilibrium concentrations are 0.371 mol/L N2O4 and 2.04 mol/L NO2 . Calculate the equilibrium constant, Kc , for this reaction. study equilibrium the effect of anxiety (low vs. high) and stress (low vs. moderate vs. high) on test.

Everyone experiences anxiety occasionally, but persistent anxiety can reduce your quality of life. Though likely best known for altering behavior, worry can have negative effects on our physical health. Anxiety speeds up our heartbeat and breathing, concentrating blood flow to the parts of our brains that need it. You are getting ready for a challenging situation by having this extremely bodily reaction. Test equilibrium may be impacted by anxiety. According to studies, pupils with low levels of test anxiety perform better on multiple-choice question (MCQ) exams than pupils with high levels of anxiety. Studies have equilibrium that female students have greater levels of test anxiety than male students.

Learn more about anxiety here:
brainly.com/question/4913240

#SPJ4

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Zielflug [23.3K]

Answer:

See explanation and image attached

Explanation:

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Two carbocations are formed leading to the major and minor products. The major product is obtained from the tertiary (more stable) carbocation while the minor product is obtained from the secondary (less stable carbocation).

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3 years ago
A container was found in the home of the victim that contained 130 g of ethylene glycol in 380 g of liquid. What was the percent
Kaylis [27]

Answer:

34.21%

Explanation:

Given parameters:

Mass of ethylene glycol in the container = 130g

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Unkown:

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Solution

To find the percentage of the ethylene glycol in liquid, we use the expression below:

Percentage of ethylene glycol in liquid = \frac{mass of ethylene glycol}{mass of liquid} x 100

Percentage of ethylene glycol = \frac{130}{380} x 100

Percentage of ethylene glycol = 34.21%

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