The answers are:
the first term: 21
the fourth term: 22
the tenth term: 39
<span>A(n) = 12+(n - 1)(3)
n = 1
A(1) = 12 + (1 - 1)(3) = 12 + 0*3 = 12 + 0 = 12
n = 4
</span>A(4) = 12 + (4 - 1)(3) = 12 + 3*3 = 12 + 9 = 21
n = 10
A(10) = 12 + (10 - 1)(3) = 12 + 9*3 = 12 + 27 = 39
Answer:
Let the speed of the train be x km/h.
Case 1:
Distance = 288 km
Speed = x km/h
Time = Distance/Speed
= 288/x h
Case 2:
Distance = 288 km
Speed = (x+4) km/h
Time = 288/x + 4 h
Since 288/x > 288/x + 4
288/x - 288/x+4 = 1
288[1/x - 1/x+4 ] = 1
[ x + 4 - x / x(x + 4) ] = 1/288
[4 / x^2 + 4x ] = 1/288
x^2 + 4x = 1152
x^2 + 4x - 1152 = 0
x^2 + 36x - 32x - 1152 = 0
x(x + 36) - 32(x + 36) = 0
(x + 36)(x - 32) = 0
x + 36 = 0 , x - 32 = 0
x = -36 , x = 32
x = -36 , rejected since speed cannot be negative.
Therefore , speed of the train = 32 km/h
Answer:
See below ~
Step-by-step explanation:
<u>sin (A) = opposing side / hypotenuse</u>
<u></u>
<u>cos(A) = adjacent side / hypotenuse</u>
<u></u>
<u>tan(A) = opposing side / adjacent side</u>
- tan(A) = 5/2 = <u>2.5</u>