All categories

3 years ago

11) HELP PLZ ASAP i dont know if I am right or wrong

Physics

2 answers:

Westkost [7]3 years ago

7 0

Position 2. I need 20 characters to post so: duhdjdjdhdhd

Elena-2011 [213]3 years ago

7 0

I’m pretty sure it’s position 2.

You might be interested in

It is MOST accurate to say the the body mass index (BMI) provides information about ____________. A. Body composition. B. An ind

cluponka [151]

It is most accurate to say that body mass index (BMI) provides information about an individual's height-weight ratio. The correct answer is B.

8 0

3 years ago

Read 2 more answers

A rock falls 15 m. is this vertical or horizontal motion? what is the displacement?

Irina-Kira [14]

Displacement will be 15 too because
It falls from 0 till 15 meters

4 0

4 years ago

Assume that the equator of the Earth is 24,000 miles long (that’s its circumference). Now, pretend that you are standing somewhe

slega [8]

Answer:

1000 mph

Explanation:

P = Perimeter = 24000 mi

r = Radius of the equator

t = Time taken to complete one rotation = 24 h

Perimeter of a circle is given by

$P=2\pi r\\\Rightarrow r=\dfrac{P}{2\pi}\\\Rightarrow r=\dfrac{24000}{2\pi}\ mi$

Angular speed is given by

$\omega=\dfrac{2\pi}{t}\\\Rightarrow \omega=\dfrac{2\pi}{24}$

Velocity if given by

$v=r\omega\\\Rightarrow v=\dfrac{24000}{2\pi}\times \dfrac{2\pi}{24}\\\Rightarrow v=1000\ mph$

The person would be going at a speed of 1000 mph

3 0

3 years ago

PLEASE HELP !!!

elixir [45]

Answer:

Explanation:

The answer is A because proton number is the same as atomic number

8 0

3 years ago

Chameleons catch insects with their tongues, which they can rapidly extend to great lengths. In a typical strike, the chameleon’

Yuki888 [10]

Answer:

0.2 m

Explanation:

PHASE 1

First, we calculate the distance the tongue moved in the first 20 ms (0.02 secs). We use one of Newton's equations of linear motion:

$s = ut + \frac{1}{2}at^2$

where u = initial velocity = 0 m/s

a = acceleration = $250 m/s^2$

t = time = 0.02 s

Therefore:

$s = 0 + \frac{1}{2} * 250 * (0.02)^2\\\\\\s = 0.05 m$

PHASE 2

Then, for the next 30 ms (0.03 secs), we use the formula:

$distance = speed * time$

This speed is the same as the final velocity of the tongue after the first 20 ms.

This can be obtained by using the formula:

$v = u + at\\\\=> v = 0 + (250 * 0.02)\\\\\\v = 5 m/s$

Therefore:

distance = 5 * 0.03 = 0.15 m

Therefore, the total distance moved by the tongue in the 50 ms interval is:

0.05 + 0.15 = 0.2 m

8 0

3 years ago