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4 years ago

What is physics and is it related to chemistry?

1 answer:

4 0

Physics also deals with the basic principles that explain matter and energy, and may study aspects of atomic matter by following concepts derived from the most fundamental principles. Chemistry focuses on how substances interact with each other and with energy (for example heat and light).

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A 14.0 g wad of sticky clay is hurled horizontally at a 110 g wooden block initially at rest on a horizontal surface. The clay s

ahrayia [7]

Answer:

86.53 m/s

Explanation:

Given:

Mass of clay (m) = 14.0 g = 0.014 kg

Mass of block (M) = 110 g = 0.110 kg

Initial speed of block (U) = 0 m/s

Sliding distance (d) = 7.50 m

Coefficient of friction between block and surface (μ) = 0.650

Let the initial speed of clay be 'u' and speed of clay and block just after collision be 'v'.

Now, momentum is conserved just before and just after collision.

Momentum just before collision = $mu + 0 = mu$

Momentum just after collision = $(m + M)v$

Therefore, $mu=(M+m)v$ --------- (1)

Now, using newton's second law and we find the acceleration of the system.

The frictional force is given as:

$f=\mu mg=-ma\\\\a=-\mu g$

Now, using equation of motion, we can find the velocity just after collision.

$0^2=v^2+2ad\\\\v=\sqrt{-2ad}\\\\v=\sqrt{-2\times (-\mu g)\times d}\\\\v=\sqrt{2\mu gd}$

Plug in the given values and find 'v'. This gives,

$v=\sqrt{2\times 0.650\times 9.8\times 7.50}\\\\v=\sqrt{95.55}=9.77\ m/s$

Now, using equation (1) and substituting the given values, we get:

$0.014u=(0.014+0.110)\times 9.77\\\\u=\frac{0.124\times 9.77}{0.014}\\\\u=86.53\ m/s$

Therefore, the speed of the clay immediately before impact is 86.53 m/s.

7 0

3 years ago

A force of 60 N is used to stretch two springs that are initially the same length. Spring A has a spring constant of 4 N/m, and

ad-work [718]

We can calculate the length of each spring by using the relationship:
$F=kx$
where
F is the force applied to the spring
k is the spring constant
x is the length of the spring (measured with respect to its rest position)

Re-arranging the equation, we have
$x= \frac{F}{k}$

The force applied to both spring is F=60 N. Spring A has spring constant of k=4 N/m, therefore its length with respect to its rest position is
$x_A= \frac{F}{k_A}= \frac{60 N}{4 N/m}=15 m$
Spring B has spring constant of k=5 N/m, so its length with respect to its rest position is
$x_B= \frac{F}{k}= \frac{60 N}{5 N/m}=12 m$

Therefore, the correct answer is
<span>D.Spring A is 3 m longer than spring B because 15 – 12 = 3.</span>

5 0

3 years ago

Read 2 more answers

Compare and contrast the sound waves produced by someone whispering and someone shouting.

andrezito [222]

1. They could have different types of sounds, so wave-shape could be different.

2. If they have the same frequency, the volume is different, so they could have different amplitudes (larger amplitude = larger sound).

3. Different frequencies based on the pitches

4 0

4 years ago

The junction rule describes the conservation of which quantity? Note that this rule applies only to circuits that are in a stead

denis-greek [22]

Explanation:

The junction rule says that the sum of the currents going into a junction must equal the sum of the currents leaving a junction. This describes the conservation of current.

5 0

3 years ago

Read 2 more answers

A bullet was fired from a gun. The bullet had a mass of 50g and the kinetic energy of the bullet was 25 kJ. How fast did it go?

Elenna [48]

Answer:

$given \: \\ mass \: (m) = 50g \\ kinetic \: enegy \: (k.e) = 25kj \\ velocity(v) = x \\ form \\ k.e = \frac{1}{2} \times MV ^{2} \\ 25 = \frac{1}{2} \times 50 \times v {}^{2} \\ 25 = 25 \times v {}^{2} \\ v {}^{2} = \frac{25}{25} \\ v {}^{2} = 1 \\ v = \sqrt{1} \\ v = 1ms {}^{ - }$

the car it go fast with velocity 1m/s

5 0

3 years ago

What is physics and is it related to chemistry? ​

What is physics and is it related to chemistry?