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frez [133]
4 years ago
8

Two identical brass balls mounted on a wooden posts initially have different amounts of charge, one +3.9 uC and the other +16.4

uC. The balls are allowed to touch and then separated again. . . What is the final charge on each ball? . .
Physics
1 answer:
laiz [17]4 years ago
8 0
When the balls touch, the charge is uniformly distributed across them. When they separate, each has half: 

<span>( 3.9 uC + 16.4 uC ) / 2 = 10.15 uC

Therefore, </span><span>the final charge on each ball is 10.15 uC.

</span><span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

</span>
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Will binoculars work properly if their prisms (assume n = 1.50) are immersed in water (nwater= 1.33)? assume that binoculars wor
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The binoculars will not work properly.

Please refer to the diagram attached.

Binoculars work on the principle of total internal reflection. The incident ray from air enters the prism through on face normally and it strikes the opposite face at an angle of 45°. The ray undergoes Total internal reflection if its critical angle is less than the angle of incidence,which , in this case is 45°.

The critical anglei_{c} is related to the refractive index of the material of glass μ as shown below.

\mu =\frac{1}{sini_c}

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sini_c=\frac{1}{\mu} \\ =\frac{1}{1.5} \\ =0.666

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\mu_g_w=\frac{\mu_g}{\mu_w}

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sinc=\frac{\mu_w}{\mu_g}

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sinc=\frac{\mu_w}{\mu_g} \\ =\frac{1.33}{1.5} \\ =0.8866

Take the inverse of the value 0.8866.

c=sin^{-1} (0.8866)\\ =62^o

Since the critical angle of the prism when immersed in water, is 62°, which is greater than the angle of incidence of 45° required for viewing the object, the binoculars which are set for Total reflection in air, will not function when immersed in water.

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4 years ago
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