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Burka [1]
4 years ago
9

During oxidation-reduction reactions, a material loses electrons to the oxidizer, which has a positive charge. Which power sourc

e directs these lost electrons through an electronic device to give it power?
A. An electric outlet
B. An electromagnet
C. An electric motor
D. A battery
Physics
2 answers:
Nikolay [14]4 years ago
3 0

Answer:

D. Battery

During the oxidation-reduction(redox) reaction, there is always flow of electrons from one point to another. The electrons are then converted to power through the battery which converts chemical energy to electrical energy. If there is zero flow of electrons then there will also be zero power.

Tems11 [23]4 years ago
3 0

Answer:

D. A battery.

Explanation:

A battery cell refers to a single anode and cathode separated by electrolyte used to produce a voltage and current. It is typically an electrolytic cell.

An electrolytic cell is an electrochemical cell that drives a non-spontaneous redox reaction through the application of electrical energy. They are often used to decompose chemical compounds, in a process called electrolysis.

The anode which is positive electrode undergoes oxidation i.e loss of electrons while the cathode(negative) undergoes reduction that is, accept electrons.

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inna [77]

Answer:

C

Explanation:

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3 years ago
Which describes what happens when fuel is ignited in a heat engine?
statuscvo [17]
Thermal energy is converted to chemical energy.
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3 years ago
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A barefoot field-goal kicker imparts a speed of 54 m/s to a football initially at rest. If the football has a mass of 0.55 kg an
il63 [147K]

Answer:

Force, F = 900 N

Explanation:

Given that,

Mass of the football, m = 0.55 kg

Initial speed of the ball, u = 0

Final speed, v = 54 m/s

Time of contact, t = 0.033 s

We need to find the magnitude of the force exerted by the ball on the kicker’s foot. It is a case of second law of motion. It is equal to the rate of change of momentum. So,

F=\dfrac{\Delta p}{\Delta t}\\\\F=\dfrac{mv}{t}\\\\F=\dfrac{0.55\times 54}{0.033 }\\\\F=900\ N

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8 0
3 years ago
Please, someone help me I'm begging yall 1. it's estimated that 1 kg of body fat will provide 3.8 * 10^7 J of energy. A 67 kg mo
Leto [7]

Answer:

0.24 kg used up

Explanation:

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W = m*g*h

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Work = 2,300,445 Joules

Work = 2300 kj

work = 2.30 * 10^6 joules in scientific notation.

Part B

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1 kg / (3.8 * 10^7 J ) = x kg / (9.20 * 10^6 J)

9.20 * 10 ^6 * 1 = 3.8 * 10^7 *x

9.20 * 10 ^6 / 3.8 * 10^7 = x

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3 years ago
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soldier1979 [14.2K]

Answer:

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Explanation:

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