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Lapatulllka [165]
3 years ago
12

A horse ran 5.75m/s for 3.5min, how far did it travel

Physics
1 answer:
quester [9]3 years ago
5 0
The unit rate is in meters per sec, so change 3.5 minutes into seconds.
3.5*60= 210 seconds

Distance= speed*time

210 seconds* 5.75 m/s= 1207.5 meters total
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A force is a push or a pull. Under the right circumstances, anything can exert a force.
Sliva [168]

Answer:

Explanation:

the force that you applied caused the notebook to move.

the force applied on the notebook by the table causes it to stop moving.

this is because after sometime the book uses up the force and later the force you applied is less than that of the force by the table.

7 0
3 years ago
A material that can be hit without shattering is?<br> viscous, flammable, hard, malleable
nika2105 [10]
Malleable

Malleability is a property of matter, that’s specializes in metals, in which these metals can be bended, twisted or formed into a thinner sheets, and not being able to shatter to pieces instead it can be formed into a new shape. Unlike the other three, take for instance hardness. If a hard object such as wood for example when used with an axe it breaks and it is lead to smithereens. Flammable like is when applied to fire can dramatically explode when hit it obviously breaks.



3 0
2 years ago
Scientists have organized all forms of energy into two types—kinetic and potential. Kinetic energy is the energy of motion, and
mihalych1998 [28]

Answer:

Potential energy only

Explanation:

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7 0
2 years ago
What us meant by Velocity ratio of simple machine is 4?<br><br><br>​
butalik [34]
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Please mark as brainliest
8 0
3 years ago
An electron is moving east in a uniform electric field of 1.55 N/C directed to the west. At point A, the velocity of the electro
valkas [14]

Answer:

Final velocity of electron, v=6.45\times 10^5\ m/s    

Explanation:

It is given that,

Electric field, E = 1.55 N/C

Initial velocity at point A, u=4.52\times 10^5\ m/s

We need to find the speed of the electron when it reaches point B which is a distance of 0.395 m east of point A. It can be calculated using third equation of motion as :

v^2=u^2+2as........(1)

a is the acceleration, a=\dfrac{F}{m}

We know that electric force, F = qE

a=\dfrac{qE}{m}

Use above equation in equation (1) as:

v^2=u^2+\dfrac{2qEs}{m}

v^2=(4.52\times 10^5\ m/s)^2+2\times \dfrac{1.6\times 10^{-19}\ C\times 1.55\ N/C}{9.1\times 10^{-31}\ kg}\times 0.395\ m

v = 647302.09 m/s

or

v=6.45\times 10^5\ m/s

So, the final velocity of the electron when it reaches point B is 6.45\times 10^5\ m/s. Hence, this is the required solution.

3 0
3 years ago
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