Answer:
3.13cm/s²
Explanation:
Given
Initial velocity u = 3.5cm/s
Final velocity v = 8.2cm/s
Time t = 1.5secs
Required
Acceleration of the cart a
To get that, we will use the equation of motion
v = u+at
Substitute the given parameters
8.2 = 3.5+1.5a
1.5a = 8.2-3.5
1.5a = 4.7
a = 4.7/1.5
a = 3.13cm/s²
Hence the acceleration to the cart is 3.13cm/s²
Answer:Because if the shape gets changed it will move faster without to much weight
Explanation:
Answer:
47 m
Explanation:
Data obtained from the question include the following:
Length of dry leg 1 (L1) = 40 m
Length of dry leg 2 (L2) = 25 m
Length of swimming course (L) =..?
The length of the swimming course can be obtained by using pythagoras theory as shown below:
L² = L1² + L2²
L² = 40² + 25²
L² = 1600 + 625
L² = 2225
Take the square root of both side.
L = √2225
L = 47.1 ≈ 47 m
Therefore, the length of the swimming course is approximately 47 m.
The net force of the object is equal to the force applied minus the force of friction.
Fnet = ma = F - Ff
12 kg x 0.2 m/s² = 15 N - Ff
The value of Ff is 12.6 N. This force is equal to the product of the normal force which is equal to the weight in horizontal surface and the coefficient of friction.
Ff = 12.6 N = k(12 kg)(9.81 m/s²)
The value of k is equal to 0.107.
