Answer:
Option 2 and 4
Step-by-step explanation:
Given : Function's graph has asymptotes located at the values 
To find : Which function graph has asymptote given?
Solution :
An asymptote is a line or curve that approaches a given curve.
To find vertical asymptote the limit has to go to either ∞ or −
∞ , which happens when the denominator becomes zero.
The sine are defined for all real x, y is defined for all real x, so there are no vertical asymptotes.
So, Option 1 is not true.
In option 3,

When we put Denominator = 0

Value of x lie between 
So, Option 3 is not true.
In Option 2,

When we put Denominator = 0

When cos x=0 the values of x is


Therefore, The graph of y= sec x has asymptote located at the values 
So, Option 2 is correct.
In Option 4,

When we put Denominator = 0

When cos x=0 the values of x is


Therefore, The graph of y= tan x has asymptote located at the values 
So, Option 4 is correct.
Therefore, Option 2 and 4 are correct.
Hence Option A is correct - 2 only