For this case we have the following functions:
When composing the functions we have:
Substituting values we have:
Rewriting:
The function has a horizontal asymptote at y = 3.
Therefore, the range of the function is all reals minus y = 3.
Answer:
option 3
Answer:
180.55 in².
Step-by-step explanation:
Data obtained from the question include the following:
Height (h) = 9 in.
Diameter (d) = 5 in
Pi (π) = 3.14
Area of the label =..?
Next, we shall determine the radius.
Diameter (d) = 5 in
Radius (r) =.. ?
Radius (r) = Diameter (d) /2
r = d/2
r = 5/2
r = 2.5 in.
Next, we shall determine the area of the label that needs to be printed to go around the new container by calculating the surface area of the cylinder.
This is illustrated below:
Height (h) = 9 in.
Pi (π) = 3.14
Radius (r) = 2.5 in.
Surface Area (SA) =.?
SA = 2πrh + 2πr²
SA = (2×3.14×2.5×9) + (2×3.14×2.5²)
SA = 141.3 + 39.25
SA = 180.55 in²
The surface area of the cylinder is 180.55 in².
Therefore, the area of the label that needs to be printed to go around the new container is 180.55 in².
Answer:
yes they are
Step-by-step explanation: because 5x2=10 and 3x2=6 see they both multiply by 2
