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2 years ago

Ax-4y=-1. (6,1) find coefficient write complete equation

Mathematics

1 answer:

Rom4ik [11]2 years ago

7 0

I think the answer is a=2

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A number is multiplied by 20, and that product is added to 5. The sum is equal to the product of 5 and 13.

liubo4ka [24]

Answer:

x = 3

Step-by-step explanation:

First, you will pick the first equation :

(x*20)

Then the next,

(x*20) + 5

Then the last equation,

(x*20) + 5 = 5*13

Then you solve

20x + 5 = 65

20x = 65 - 5

20x = 60

20x/20 = 60/20

x = 3

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2 years ago

Find two number nearest to 8888888 which are exactly divisible by 2915

Marysya12 [62]

Step-by-step explanation:

Given problem is to find nearest number,

= 8888888/2915

quotient = 3049

remainder= 1053

Now, 2915-1053 = 1862

8888888+1862 = 8890750

8888888-1053 = 8887835

Two numbers nearest to 8888888 which are exactly divisible by 2915 is 8887835 and 8890750

3 0

2 years ago

Evaluate the expression for x = 1.7. Enter your answer in the box.<br> x2 + 3x

S_A_V [24]

Answer: 6

Step-by-step explanation:

4 0

2 years ago

The ages of the 11 players of a soccer team on the soccer field are shown 21,32,22,28,26,30,29,24,22,24,26

bekas [8.4K]

Answer:

B is the answer of the following question...

I hope it is correct !

7 0

3 years ago

Read 2 more answers

Three people pull simultaneously on a stubborn donkey. Jack pulls directly ahead of the donkey with a force of 90.5 N , Jill pul

Radda [10]

Answer:

Fn= 174.9 N : Magnitude of the net force the people exert on the donkey.

Step-by-step explanation:

We find the components of the forces in x-y-z

Force of Jack in z =F₁z=90.5 N in direction (+z)

Force of Jill in x = F₂x= -82.3*cos45°= - 58.19 N (-x)

Force of Jill in y =F₂y=-82.3*sin45°= + 58.19 N (+y)

Force of Jane in x =F₃x=125*cos45°= + 88.4 N (+x)

Force of Jane in y =F₃y=125*sin45°= + 88.4 N (+y)

Calculating of the components of the net force the people exert on the donkey.

Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)

Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)

Fnz =F₁z=90.5 N (+z)

Calculating of the magnitude of the net force the people exert on the donkey.

$F_{n} =\sqrt{(F_{nx})^{2}+(F_{ny}) ^{2} +(F_{nz}) ^{2} }$

$F_{n} =\sqrt{(30.2)^{2}+( 146.59) ^{2} +(90.5) ^{2} }$

$F_{n} = 174.9 N$

7 0

3 years ago