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Sonbull [250]
4 years ago
13

How many 5 digit numbers can be formed using the digits 0,1,2,3,4,5,6 if repetition of digits is not allowed

Mathematics
1 answer:
Elodia [21]4 years ago
5 0
6!=6*5*4*3*2*1=720
Pretty sure this is correct
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The Positive Z-Equal Line, the Negative Z-Equal Line, and the Regression Line all pass through the same point. What are the stan
Evgen [1.6K]

Answer:

The standard coordinates of the point are ; ( 0,0 )

Step-by-step explanation:

The standard coordinates of the point are ; ( 0,0 ) also the standard values of the means will also be ( 0, 0 )

This is because for the Positive Z-equal line, Negative Z-Equal line and Regression line to all pass through the same point indicates dependent and independent variables of the Z-score and regression lines respectively

4 0
3 years ago
johnathan class has 30 boys of the students in his class 60% are girls how many girls are in johnathans class
Gekata [30.6K]

Answer:

45 girls

Step-by-step explanation:

If 60% of the class is girls then 40% of the class is boys.

30 boys are in the class, meaning that 40% of the class comprises those 30 boys

First, we need the total number of class members: 30/x = 40/100 -> 40x=3000 -> x=3000/40 -> x=75

Now that we know the total class members, at 75, we can calculate the number of girls in the class. You can do this:

0.6*75=45

or

60/100=x/75 and solve for x

5 0
4 years ago
Solve:<br> y = 2x -11<br> -3y = -6x -15
Nikolay [14]

9514 1404 393

Answer:

  no solution (parallel lines)

Step-by-step explanation:

You observe that the coefficient in the second equation are all multiples of 3. Dividing that equation by -3 gives the two equations ...

  • y = 2x - 11
  • y = 2x + 5

The slopes are the same (2) and the intercepts are different (-11, 5), so the lines are parallel. There is no solution.

7 0
3 years ago
Describe how you labeled the bar model and wrote a number sentence to solve.
alukav5142 [94]
By answering the question and reading the question
3 0
3 years ago
Expand »
Stolb23 [73]
Imani=i
Miguel=m

i=2m+3
i+m=87
i=-m+87
2i=m+90
i=(m+90)/2
2m+3=(m+90)/2
2m+3=m/2+45
4m+6=m+90
3m+6=90
3m=84
m=28

Hope this helps :)
3 0
4 years ago
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