Answer:
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Explanation:
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1. mol ratio of Al(NO₃)₃ : Na₂CO₃ = 2 : 3
2. Na₂CO₃ as a limiting reactant
<h3>Further explanation</h3>
Given
Reaction
2 Al(NO₃)₃ + 3 Na₂CO₃ → Al₂(CO₃)₃ + 6 NaNO₃
Required
mol ratio
Limiting reactant
Solution
The reaction coefficient in the chemical equation shows the mole ratio of the components of the compound involved in the reaction (reactants and products)
1. From the equation mol ratio of Al(NO₃)₃ : Na₂CO₃ = 2 : 3
2. mol : coefficient of Al(NO₃)₃ : Na₂CO₃ = 2 mole/2 : 2 mole/3 = 1 : 0.67
Na₂CO₃ as a limiting reactant (smaller)
Solute and solvent form a solution, which means two different kinds of molecules/atoms/compounds are mixed together, therefore, it is a mixture.
No because the one valence electron it had is gone so it’s not stable hope this helps
The amount of Calcium hydroxide : = 58.719 g
<h3>Further explanation</h3>
Given
100 g Nitric Acid-HNO₃
Required
The amount of Calcium hydroxide
Solution
Reaction(balanced) :
Ca(OH)₂ (s) + 2HNO₃ (aq) → Ca(NO₃)₂ (aq) + 2H₂O (l)
mol of Nitric acid (MW 63 g/mol) :
mol = mass : MW
mol = 100 : 63
mol = 1.587
From the equation, mol ratio of Ca(OH)₂ : HNO₃ = 1 : 2, so mol Ca(OH)₂ :
=1/2 x mol HNO₃
= 1/2 x 1.587
=0.7935
Mass of Ca(OH)₂ (MW=74 g/mol) :
= mol x MW
= 0.7935 x 74
= 58.719 g