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3 years ago

What determines whether something is a solid, a liquid or a gas?

Chemistry

2 answers:

umka21 [38]3 years ago

5 0

Also, how fast the molecules are moving within the state of matter and how spread out they are.

boyakko [2]3 years ago

4 0

Answer:

the properties of the molecules in it

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What are the products of the following neutralization reaction (No need to balance)

Nina [5.8K]

HCI + NaOH --> NaCl + H2O

Neutralization reaction is the reaction between acid and base which results in formation of salt and water. Here salt is NaCl (common salt) in above reaction.

SO, (A) H20 + NaCl is your answer.

8 0

3 years ago

Sulfur dioxide, SO 2 ( g ) , can react with oxygen to produce sulfur trioxide, SO 3 ( g ) , by the reaction 2 SO 2 ( g ) + O 2 (

aleksley [76]

Answer: The amount of heat produced by the reaction is -21.36 kJ

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]$

For the given chemical reaction:

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(SO_3(g))})]-[(2\times \Delta H_f_{(SO_2(g))})+(1\times \Delta H_f_{(O_2(g))})]$

We are given:

$\Delta H_f_{(SO_2(g))}=-296.8kJ/mol\\\Delta H_f_{(SO_3(g))}=-395.7kJ/mol\\\Delta H_f_{(O_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(2\times (-395.7))]-[(2\times (-296.8))+(1\times (0))]\\\\\Delta H_{rxn}=-197.8kJ/mol$

To calculate the number of moles, we use ideal gas equation, which is:

$PV=nRT$

where,

P = pressure of the gas = 1.00 bar

V = Volume of the gas = 2.67 L

n = number of moles of gas = ?

R = Gas constant = $0.0831\text{ L. bar }mol^{-1}K^{-1}$

T = temperature of the mixture = $25^oC=[25+273]K=298K$

Putting values in above equation, we get:

$1.00bar\times 2.67L=n\times 0.0831\text{ L. bar }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1\times 2.67}{0.0831\times 298}=0.108mol$

To calculate the heat released of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

q = amount of heat released = ?

n = number of moles = 0.108 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = -197.8 kJ/mol

Putting values in above equation, we get:

$-197.8kJ/mol=\frac{q}{0.108mol}\\\\q=(-197.8kJ/mol\times 0.108mol)=-21.36kJ$

Hence, the amount of heat produced by the reaction is -21.36 kJ

3 0

3 years ago

The compound zinc fluoride is a strong electrolyte. write the transformation that occurs when solid zinc fluoride dissolves in w

Svetach [21]

Strong electrolytes by definition are those compounds that completely dissociates into their component ions when dissolved in water. The chemical formula for the zinc fluoride is,
ZnF2
This means that each formula unit is composed of one atom of zinc and 2 atoms of fluoride. The ions comprising the unit are Zn²⁺ and F⁻. The dissociation is as shown below,
ZnF₂ --> Zn²⁺ + 2F⁻
When dissolved in water it is expected that the compound dissociates into three different ions, one Zn²⁺ and two F⁻.

4 0

3 years ago

Na + O2 → Na2O2 Can you guys help me !

vfiekz [6]

Answer:

Explanation:

Assuming that you are asking for the full-balanced equations...

2Na + O2 = Na2O2

H2 + O2 = H2O2; This equation is already balanced, there is no need for change.

Please let me know if this is not the answer you are looking for and I will amend the answer.

6 0

3 years ago

Balance the following chemical equations. Questions 6-10

aleksandr82 [10.1K]

6. Put a 2 before H2O, and a 4 before HF
7. Just put a 2 before HCI
8. I can't seem to figure this one out...sorry. I can keep trying if you want tho...
9. Put a 2 before HNO3 and a 3 in front of O2
10. I think you just put a 2 in front of H2O.
I tried my best. I hope I got at least one right...I started this stuff yesterday..good luck

4 0

3 years ago