Answer:
0.0831 moles of NaOH were in the original mixture
Explanation:
The strontium hydroxide, Sr(OH)2, requires 2 moles of HCl per mole of hydroxide to be neutralized.
The sodium hydroxide, NaOH, requires 1 mol of HCl per mol of hydroxide.
To solve this question we must write 2 equations:
<em>(1) </em>0.19mol = X + Y
<em>Where X = Moles NaOH; Y = Moles Sr(OH)2</em>
The moles of HCl required are:
0.100L * (2.969mol / L) = 0.2969 moles HCl
0.2969 mol = X + 2Y<em>(2)</em>
Replacing (1) in (2):
0.19mol - Y = X
0.2969 mol = (0.19mol - Y) + 2Y
0.1069mol = Y
Moles X = Moles NaOH:
0.19mol = X + 0.1069mol
X = 0.0831 moles of NaOH were in the original mixture
A. because atoms create crystal structures to form different kind of materials
Percentage Weight-in-volume is defined as the <em><u>number of grams of a solute in a 100 ml (milliliters) solution.</u></em>
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<u>Percentage Weight-in-volume</u> can tell us about the <em>degree of concentration of a given solution.</em>
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The solute can be <em>crystalline or non-crystalline in nature.</em>
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The <u>number of grams of glucose</u> present in a <u>5% glucose solution</u> is 5 grams.
- This question is based on a Percentage Weight-in-volume. The formula states that:
a% of a glucose solution =<u> a grams of glucose in a 100 mL solution</u>
Hence, 5% glucose solution = 5 grams of glucose / 100 mL solution
Therefore, the <u>number of grams of glucose</u> present in a <u>5% glucose solution</u> is 5 grams.
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Although there exists a dipole moment in the molecule, I guess its nonpolar because the dipole is very small as the electronegativity difference between the Br and Cl is very low and so it can be neglected.
Answer: At STP, a mole of gas takes up 22.4 Liters. The 22.4 Liters/mole quantity can be derived from the Ideal Gas Law, PV = nRT, plugging in STP conditions for P and T, and solving for V/n, which gets 22.4 Liters/mole.
Explanation:
