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3 years ago

14

debbie is making bows that use 1/6 yards of ribbion each, if debbie has 2 yards of ribbion, how many bows can she make? write a

division equation and multipcation equation to show this

1 answer:

Bezzdna [24]3 years ago

3 0

Answer:

She can make 12 bows ......................................

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Find the value of x for which m is parallel to n <br> A) 10<br> B) 12<br> C) 40<br> D) 52

Klio2033 [76]

Answer: $x=5\textdegree$

Explanation:

Since we have given that

line m and line n are parallel to each other,

So,

Corresponding angles are equal , as shown in the figure ,

According to question,

$19x\textdegree=180\textdegree-17x\textdegree\\\\19x\textdegree+17x\textdegree=180\\\\36x\textdegree=180\textdegree\\\\x=\frac{180}{36}\\\\x=5\textdegree$

Hence, $x=5\textdegree$

6 0

3 years ago

How do you know if this equation is true 1/3+1/5=2/8=1/4

raketka [301]

4/16 or 1/4 because 1 + 1 + 2 is 4 & 3 + 5 + 8 is 16 so the fraction will be 4/16 but u can also divide both by 4’s which is 1/4.

7 0

3 years ago

Which of the following is a perfect square? <br> A. 13 <br> B. 127 <br> C. 100 <br> D. 102

shusha [124]

D is a perfect square

5 0

3 years ago

Read 2 more answers

How do I <br> evaluate 32-4x3

yawa3891 [41]

Answer:

20

Step-by-step explanation:

Evaluate is just simplifying so

4 times 3 is 12 times the negative makes it -12

then add 32 and -12 together

and you get 20

8 0

2 years ago

Read 2 more answers

Three forces act on a hook. Determine the magnitude of the resultant of the force.

Novay_Z [31]

Use Hooke's law... (just kidding)

Break down each force vector into horizontal and vertical components.

$\vec F_1=(1000\,\mathrm N)(\cos30^\circ\,\vec x+\sin30^\circ\,\vec y)\approx(866.025\,\mathrm N)\,\vec x+(500\,\mathrm N)\,\vec y$

$\vec F_2=(1500\,\mathrm N)(\cos160^\circ\,\vec x+\sin160^\circ\,\vec y)\approx(-1409.54\,\mathrm N)\,\vec x+(513.03\,\mathrm N)\,\vec y$

$\vec F_3=(750\,\mathrm N)(\cos195^\circ\,\vec x+\sin195^\circ\,\vec y)\approx(-724.444\,\mathrm N)\,\vec x+(-194.114\,\mathrm N)\,\vec y$

The resultant force is the sum of these vectors,

$\vec F=\displaystyle\sum_{i=1}^3\vec F_i\approx(-1267.96\,\mathrm N)\,\vec x+(818.916\,\mathrm N)\,\vec y$

and has magnitude

$|\vec F|\approx\sqrt{(-1267.96\,\mathrm N)^2+(818.916\,\mathrm N)^2}\approx1509.42\,\mathrm N$

The closest answer is D.

5 0

2 years ago