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Mamont248 [21]
3 years ago
8

Which factor affects the solubility of a substance but not the rate at which it dissolves? A. stirring B. surface area C. temper

ature D. molecular polarity
Chemistry
2 answers:
dusya [7]3 years ago
8 0
. the correct answer is D molecular polarity
Dovator [93]3 years ago
6 0

Answer: Option (D) is the correct answer.

Explanation:

Polarity is defined as the presence of charges (positive or negative) present on the atoms of a compound or molecule.

For example, NaCl is a polar molecule because it has ionic bond whereas CCl_{4} is a non-polar molecule.

Also, it is known that like dissolves like that is, a polar molecule is soluble in a polar solvent whereas a non-polar molecule is soluble in a non-polar solvent.

When we stir, increase the surface area, and increase the temperature for a solution then rate of reaction also changes but molecular polarity does not affect the rate of a reaction.

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Neutrons: 140

***REMEMBER: There is always the same amount of protons and electrons. :)

7 0
2 years ago
If 45.0 mL of ethanol (density=0.789 g/mL) initially at 9.0 C is mixed with 45.0 mL of water (density=1.0 g/mL) initially at 28.
Klio2033 [76]

Answer : The final temperature of the mixture is 22.7^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

And as we know that,

Mass = Density × Volume

Thus, the formula becomes,

(\rho_1\times V_1)\times c_1\times (T_f-T_1)=-(\rho_2\times V_2)\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of ethanol = 2.3J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of ethanol

m_2 = mass of water

\rho_1 = density of ethanol = 0.789 g/mL

\rho_2 = density of water = 1.0 g/mL

V_1 = volume of ethanol = 45.0 mL

V_2 = volume of water = 45.0 mL

T_f = final temperature of mixture = ?

T_1 = initial temperature of ethanol = 9.0^oC

T_2 = initial temperature of water = 28.6^oC

Now put all the given values in the above formula, we get

(0.789g/mL\times 45.0mL)\times (2.3J/g^oC)\times (T_f-9.0)^oC=-(1.0g/mL\times 45.0mL)\times 4.18J/g^oC\times (T_f-28.6)^oC

T_f=22.7^oC

Therefore, the final temperature of the mixture is 22.7^oC

4 0
3 years ago
Investigate and explain that when a force is applied to an object but it does not move, it is because another opposing force is
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Answer:

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3 years ago
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Elements in Group 4A
steposvetlana [31]

Answer:

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Explanation:

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How many moles of oxygen are necessary to react completely with four moles of propane (CH)?
steposvetlana [31]

Answer:

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Explanation:

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