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wlad13 [49]
3 years ago
10

What chemical change causes cake to rise?

Chemistry
1 answer:
maks197457 [2]3 years ago
3 0

Answer:

Sodium bicarbonate (NaHCO3)

Explanation:

which is also called baking soda is added during baking of a cake. It reacts with water that is added in the dough and produces carbon dioxide gas, which expands on heating and makes the cake fluffy. Thus, this is a chemical change that causes cake to rise.

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Element
Svetllana [295]

Answer:

Number of moles = 10.6 mol

Explanation:

Given data:

Molar mass of H = 1.008 g/mol

Molar mass of C = 12.01 g/mol

Molar mass of O = 16.00 g/mol

Mass of citric acid = 2.03 kg (2.03×1000 = 2030 g)

Number of moles of citric acid = ?

Solution:

Formula:

Number of moles = mass/molar mass

Now we will calculate the molar mass of citric acid:

C₆H₈O₇ = (12.01× 6) + (1.008×8) + (16.00×7)

C₆H₈O₇ = 72.06 + 8.064+112

C₆H₈O₇ = 192.124g/mol

Number of moles = 2030 g/ 192.124g/mol

Number of moles = 10.6 mol

7 0
3 years ago
Electrons involved in bonding between atoms are____.
mariarad [96]

Answer:

valence electrons

8 0
3 years ago
The wavelength of a given region of the electromagnetic spectrum ranges from 1 x 10-11 - 1 x 10-8 meters. Which waves are found
ss7ja [257]
The electromagnetic spectrum consists of the full range of known electromagnetic waves. And among them, X-rays has the wavelength of the region 1*10-11 to 1*10-8 meters.
5 0
3 years ago
How are all atoms alike
Andru [333]

Because all atoms are made from the same particles which are protons, neutrons, and electrons.

Hope this helped!!!

8 0
3 years ago
Hydrogen iodide, HI, is formed in an equilibrium reaction when gaseous hydrogen and iodine gas are heated together. If 20.0 g of
Kaylis [27]

Answer: D. 19.9 g hydrogen remains.

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of H_2

\text{Number of moles}=\frac{20.0g}{2g/mol}=10.0moles

b) moles of I_2

\text{Number of moles}=\frac{20.0g}{254g/mol}=0.0787moles

H_2(g)+I_2(g)\rightarrow 2HI(g)

According to stoichiometry :

1 mole of I_2 require 1 mole of H_2

Thus 0.0787 moles of l_2 require=\frac{1}{1}\times 0.0787=0.0787moles of H_2

Thus l_2 is the limiting reagent as it limits the formation of product and H_2 acts as the excess reagent. (10.0-0.0787)= 9.92 moles of H_2are left unreacted.

Mass of H_2=moles\times {\text {Molar mass}}=9.92moles\times 2.01g/mol=19.9g

Thus 19.9 g of H_2 remains unreacted.

5 0
3 years ago
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