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KonstantinChe [14]
3 years ago
14

What volume of 0.200 m hcl is required for the complete neutralization of 2.00 g of nahco3 (sodium bicarbonate)?

Chemistry
1 answer:
Umnica [9.8K]3 years ago
6 0
The reaction between HCl and NaHCO3 will be;
HCl + NaHCO3 = NaCl + CO2 + H2O
The relative formula mass of NaHCO3 is 84 g/mol
Moles of NaHCO3 in 2 g will be; 2/84 =0.0238 moles
The mole ratio of HCl and NaHCO3 is 1;1
Thus, the number of moles of HCl is 0.0238 moles
 The volume of HCl will be;
  = 0.0238 moles/0.2 
  = 0.119 liters or 119 cm³
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2 molecules of N2, because the hydrogen is the limiting reactant, leaving there to be more N (4 molecules) so those 4 molecules create 2 N2 molecules.
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Which element is smaller is atomic size?
Ganezh [65]

Answer:

Scandium is the smallest element of the four

Explanation:

Vanadium = 50.9415 u

Titanium = 47.867 u

Scandium = 44.955912 u

Chromium = 51.9961 u

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How many grams of nickel (+2) are required to replace all of the silver when 15.55 grams of AgNO3 are present?
Karolina [17]

2AgNO3 + Ni2+  = Ni(NO3)2 + 2Ag<span>+</span>

From the reaction, it can be seen that AgNO3 and Ni2+ has following amount of substance relationshep:

n(AgNO3):n(Ni)=2:1

From the relationshep we can determinate requred moles of Ni2+:

n(AgNO3)=m/M= 15.5/169.87=0.09 moles

So, n (Ni)=n(AgNO3)/2=0.045 moles

Finaly needed mass of Ni2+ is:

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8 0
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Which two systems are represented in this model?
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4 0
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Read 2 more answers
A propane stove burned 470 grams propane and produced 625 grams of water (this is the actual yield) C3H8 +5O2=3CO2+4H20. What wa
Liula [17]

Answer:

81.3%

Explanation:

Step 1:

The balanced equation for the reaction:

This is shown below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Step 2:

Data obtained from the question. This includes:

Mass of propane (C3H8) = 470 g

Actual yield of water (H2O) = 625 g

Percentage yield of water (H2O) =?

Step 3:

Determination of the mass of propane (C3H8) burned and the mass of water (H2O) produce from the balanced equation. This is illustrated below:

C3H8 + 5O2 —> 3CO2 + 4H2O

Molar Mass of C3H8 = (3x12) + (8x1) = 36 + 8 = 44g/mol

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Mass of H2O from the balanced equation = 4 x 18 = 72g

From the balanced equation above,

44g of C3H8 was burned and 72g of H2O was produced.

Step 4:

Determination of the theoretical yield of H2O. This is illustrated below:

From the balanced equation above,

44g of C3H8 produced 72g of H2O.

Therefore, 470g of C3H8 will produce = (470x72)/44 = 769.09g of H2O.

Therefore, the theoretical yield of H2O is 769.09g

Step 5:

Determination of the percentage yield of water (H2O). This is illustrated below:

Actual yield of water (H2O) = 625g

theoretical yield of H2O = 769.09g

Percentage yield of water (H2O) =?

Percentage yield = Actual yield/Theoretical yield x100

Percentage yield = 625/769.09 x100

Percentage yield = 81.3%

Therefore, the percentage yield of water (H2O) is 81.3%

4 0
3 years ago
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