Answer:
a) Ф = 0
b) P_avg=2*P_avg,1
Explanation:
<u>Givens:</u>
The phase difference is 0, 0.2λ, or 0.5λ between the waves.
<u>Part a: </u>
since the amplitude of the wave is directly proportional to the average rate so that the waves will transport greater energy when Ф = 0
Part b:
The two waves are identical to the first wave, the net amplitude is twice the first waves and the travel in the same tube thus
P_avg=2*P_avg,1
Answer:
Intensity at 45 cm will be 0.2283 volt
Explanation:
We have given that intensity of signal measured by the detector is 0.74 volt at a distance of 25 cm
We know that intensity of signal is given by
, here s is strength of light and r is distance
So 

In second case
Intensity is given by 
So 
Answer:
The work done by the force is 6μJ
Explanation:
Suppose, A 30 nC charge is moved from a point where V₁ = 130 V to a point where V₂ = -70 V.
We need to calculate the work done by the force
Using formula of work done

Where, q = charge
=potential difference
Put the value into the formula




Hence, The work done by the force is 6μJ.
Then he fell in a sewer with lots of poop and you try to escape but a river of pee came rushing down and wash you away
Answer:B
Explanation:i took the test believe me