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hichkok12 [17]
3 years ago
13

A wave with a large amplitude has a lot of             a.vibration  b.speed   c.energy    

Physics
2 answers:
adoni [48]3 years ago
6 0
<span>A wave with a large amplitude has a lot of             a.vibration  b.speed  <u> c.energy</u></span>
Nastasia [14]3 years ago
5 0

Answer:

<em />

<em>A high amplitude wave carries a large amount of energy; a low amplitude wave carries a small amount of energy. The average amount of energy passing through a unit area per unit of time in a specified direction is called the intensity of the wave.</em>

<u><em /></u>

<u><em>Enjoy.</em></u>

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A shop-vac is capable of pulling in air at a rate of 210 ft^3/min. what is the rate of the vacuum's air flow in l/s?
Nadya [2.5K]

The correct answer is 99.06 .

Since we know that,

1 ft = 12 inches, (1ft)3 = (12)3inches3

& 1 inch = 2.54 cm ,  (1 inch)3 = (2.54)3cm3

& 1 cm3 = 1ml,

&(1 ml)/1000 = 1L, so (1cm3)/1000 = 1L.

& 1 min. = 60 sec.

Now, 1ft3 = (12)3x(2.54)3/(1000) L

and 1 min = 60 sec

So, 1ft3/min = (12)^3x(2.54)^3/(1000)x(60) L/s

Hence 210 ft3/min = 210x(12^)3x(2.54)^3/(1000)x(60).

= 99.06.

Learn more about rate of the vacuum's air flow here :-

brainly.com/question/24641042

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3 0
2 years ago
A temperature measuring device should be placed in the __________ area of the refrigerated holding unit.
STatiana [176]
<span>A temperature measuring device should be placed in the "warmest" area of the refrigerated holding unit. The reason for this is because all foods must be stored in the minimum temperature required. If not stored properly the foods become hazardous. It is important to place the thermometer in the accurate location in reference to this question it is in the warmest location. The reasoning behind this is that if placed in the coldest location it may not represent an accurate temperature based on the entire unit.</span>
6 0
4 years ago
Your electric drill rotates initially at 5.35 rad/s. You slide the speed control and cause the drill to undergo constant angular
Agata [3.3K]

Answer:

The  angular displacement  is  \theta  =  29.6 \ rad

Explanation:

From the question we are told that

     The initial angular speed is  w =  5.35 \ rad/s

      The angular acceleration is  \alpha  =  0.331 rad /s^2

      The time take is  t =  4.81 \ s

     

Generally the angular displacement is mathematically represented as

          \theta  =  w * t  + \frac{1}{2} \alpha  * t^2

substituting values

         \theta  =  5.35 * 4.81  + \frac{1}{2}  *  0.331  * (4.81)^2

         \theta  =  29.6 \ rad

3 0
3 years ago
look around you to find an object in motion .describe the objects motion by discussing its position and direction of motion in r
VARVARA [1.3K]
An example you could use for this would be if you threw a pencil across the room 10m away. the pencil would have travelled 10m(N). you could determine the objects speed by using the formula speed=distance/time. you would have had to time how long it took for the pencil to hit the 10m marking and divide 10 by however many seconds it took.
7 0
4 years ago
To construct an oscillating LC system, you can choose from a 11 mH inductor, a 6.0 μF capacitor, and a 4.2 μF capacitor. What ar
Free_Kalibri [48]

Answer:

a. 475.14 Hz

b. 1959 Hz

c. 2341.53 Hz , 3053.34 Hz

Explanation:

f = \frac{1}{2\pi*\sqrt{C*L}}

a. smallest use the capacitive 4.2 uF + 6.0 uF = 10.2uF  replacing:

f = \frac{1}{2\pi*\sqrt{C*L}}f=\frac{1}{2\pi*\sqrt{10.2uF*11mH}}

f = 475.14 Hz

b. second smallest use the capacitive 6 uF so:

f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{6uF*11mH}}

f = 1959Hz

c. second largest and largest oscillation first combination so:

Use 4.2 uF

f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{4.2uF*11mH}}

f = 2341.53 Hz

And finally largest oscillation cap in serie so:

C=\frac{c_1*c_2}{c_1+c_2}=\frac{4.2uF*6.0uf}{4.2uf+6.0uF}

C=2.47 uF

f = \frac{1}{2\pi*\sqrt{C*L}}=f = \frac{1}{2\pi*\sqrt{2.47uF*11mH}}

f =  3053.34 Hz

5 0
3 years ago
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