Answer:
the sun is larger than the moon so it creates a shadow
Most likely, the light wave will be absorbed by the wall. Without any information as to the size and color of the wall, the location and size of the hole, or the location of the light wave, this is a generalized probability problem. For all of the places the light could be, it's more likely that it hits the wall than the hole (if the hole is less than 50% of the area of the wall).
Answer:
Explanation:
From the given information:
Since both stars are in the same cluster, the magnitude and luminosity relationship can be calculated as:

Given that;
m_1 = 1 and
m_2 = 4
Therefore,


Making
the subject of the formula:

=15.84
≅ 16
Hence, we can conclude that star X is more luminous by a factor of 16
Answer:
The solved problem is in the photo. Hope it helps.