It does not exist because the function is not continuous at -2.
Substitute -2 into both rules and they must equal the same number.
USING a TI-83 plus press Y= in Y1 put (2x+5)(x<-2) and in Y2 put (x+4)(x≥-2)
Arrow over in front Y1 and press ENTER until you see only 3 diagonal dots
Do the same in front of Y2.
Inequality signs are under 2nd MATH
Press GRAPH (You can see it is not continuous at -2)
Unfortunately, Katie will be $20 short
She has $40
Plus the $38 x 5 she will be earning which is $190
$190+$40 is $230
Looks like Kate needs one more day of hard work to get her bike ; )
Just answered this one, 15<span>(<span>6−g</span>)</span><span>=<span><span>(15)</span><span>(<span>6+<span>−g</span></span>)</span></span></span><span>=<span><span><span>(15)</span><span>(6)</span></span>+<span><span>(15)</span><span>(<span>−g</span>)</span></span></span></span><span>=<span>90−<span>15g</span></span></span><span>=<span><span>−<span>15g</span></span>+<span>90</span></span></span>
No because distributive property only for multiplication
Answer:
A=3(π/2)-1 au
Step-by-step explanation:
we have according to the graph that
f(x)=3
g(x)=cos(x)
Knowing A=∫|f(x)-g(x)|dx, then
; where a=0 and b=π/2
A=(3x-sin(x)) evaluated 0 ≤ x ≤ π/2
A=(3(π/2)-sin(π/2))-(3.0-sin(0))
