Answer:
a) By the Central Limit Theorem, 16%.
b) 0.0367 = 3.67%
c) We expect 16% orange candies, give or take 3.67%.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For samples of size n of a proportion p, the expected sample percentage is p and the standard error is ![s = \sqrt{\frac{p(1-p)}{n}}](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%7D)
In this problem, we have that:
![p = 0.16, n = 100](https://tex.z-dn.net/?f=p%20%3D%200.16%2C%20n%20%3D%20100)
a. What value should we expect for our sample percentage of orange candies?
By the Central Limit Theorem, 16%.
b. What is the standard error?
![s = \sqrt{\frac{0.16*0.84}{100}} = 0.0367](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%7B%5Cfrac%7B0.16%2A0.84%7D%7B100%7D%7D%20%3D%200.0367)
0.0367 = 3.67%
c. Use your answers to fill in the blanks below. We expect ____% orange candies, give or take _____%.
We expect 16% orange candies, give or take 3.67%.