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SVETLANKA909090 [29]
3 years ago
11

A: What are the solutions to the quadratic equation x^2+9=0?

Mathematics
1 answer:
Nataliya [291]3 years ago
3 0

Answer:

Part A)

x=-3i

x=3i

Part B)

(x+3i)(x-3i)

Step-by-step explanation:

Given:

Part A)

x^2+9=0

x^2=-9

x= √-9

x=√-1 *√9

x=± i *3

x=±3i

Part B)

x^2+9=0

x^2 - (-9)=0

x2-(3i)^2=0

(x-3i)(x+3i)=0 !

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I need help knowing how to show the work and how to get the answer and the answer it self
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Now for the two quarter circles, we know that if we put these two together we will end up with a semi-circle with radius 5 cm. The formula for the area of a circle is:

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4 0
3 years ago
Write x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers.
Mariulka [41]
X² − 6x + 7 = 0

Let's complete the square [x²-6x+(??)²] -(??)² +7 = 0

As you noticed we have added the unknown square & also subtract the same so that not to change the equation

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We know that the middle term (6x) is twice the square root of the 1st times the square root of the 2nd, That is 6x=2x (multiply) √(??)²

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