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viva [34]
3 years ago
6

Why does a reaction slow down with time?

Chemistry
1 answer:
Alex777 [14]3 years ago
8 0
As a reaction proceeds the concentration of the reactants will get lower. Since reactions occur due to collisions that are in the correct orientation and lower concentrations leads to a lower amount of collisions, lower concentrations result in lower reaction rates. I hope this helps. Let me know if anything is unclear.
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Explain why unboiled water can be used to prepare an acetic acid solution, but not a naoh solution?
shtirl [24]
NaOH is a hygroscopic compound, which means that it has a very strong affinity for water. Moreover, NaOH is also a stronger base than acetic acid is a strong acid. These two properties of NaOH make it necessary for different precautions to be taken while preparing a solution. 
On the other hand, acetic acid is not very reactive and may easily be prepared in a solution of unboiled water.
8 0
4 years ago
Sports drinks contain sugar, salt, and flavorings dissolved in water . They can be made more or less sweet by adding different a
givi [52]

Answer:

It's a mixture.

Explanation:

Answer from Edgenuity

8 0
3 years ago
Which of these solids is insoluble in water?
eimsori [14]
The answer would be A) sand, it is not soluble in water
5 0
3 years ago
Read 2 more answers
Fill in the blanks below.
Elenna [48]

Answer:

Explanation:

6CO₂ + 6 H₂O ⇄ C₆H₁₂0₆ + 6O₂

This is the chemical equation given .

1. The equation shows a __Chemical equation_______the breaking and forming of chemical bonds that leads to a change in the composition of matter.

2. In the equation, CO₂ is a___reactant_____.

3. In the equation, C₆H₁₂0₆ is a ___product________.

4. In O₂, the type of bond that holds the two oxygen atoms together is a_nonpolar_covalent bond_________.

5. In H₂O, the type of bond that holds one of the hydrogen atoms to the oxygen atom is a__polar_hydrogen bond____.

6. The number of oxygen atoms on the left side of the equation is__equal to_________ the number of oxygen atoms on the right side.

5 0
3 years ago
Calculate the percent activity of the radioactive isotope strontium-89 remaining after 5 half-lives.
maria [59]
The answer to this question would be: 3.125%

Half-life is the time needed for a radioactive molecule to decay half of its mass. In this case, the strontium-89 is already gone past 5 half lives. Then, the percentage of the mass left after 5 half-lives should be:
100%*(1/2^5)= 100%/32=3..125%
5 0
3 years ago
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