Answer:
A. The reaction will proceed forward forming more CH4
B. The reaction will proceed forward forming more CH4
C. Since the reaction is exothermic, raising the temperature will cause the reaction to proceed backward, thus forming C and H2.
D. Lowering the volume makes the gas particles to be more close together thereby enhancing their collisions leading to reaction. Therefore the reaction will proceed forward forming more CH4
E. Catalyst only reduce the activation energy so the reaction can proceed faster. The reaction will proceed forward forming.
F. The following will favour CH4 at equilibrium
i. Catalyst to the reaction mixture,
ii. Both adding more H2 to the reaction mixture and lowering the volume of the reaction mixture
iii. Adding more C to the reaction mixture.
The melting point of pure lead : 327 °C
<h3>Further explanation</h3>
Given
Amount of tin and melting point of solder
Required
The melting point
Solution
The composition of solder = tin and lead
So if it is 100% tin, 0% lead or 0% tin, 100% lead
From the table it is shown that when the position is 100% tin in the solder, the melting point of the solder is 232 °C, so it shows that the melting point of pure lead is obtained when% tin in solder = 0 (100% lead in solder), so that the melting point is obtained. : 327 °C
Answer: form hydrogen bonds to the polar water molecules.
Explanation:
Answer:
Explanation:
Particles of benzene vapors are more energetic because of benzene vapours have gained extra energy in the form of latent heat of vaporisation. Hence it is more energetic.