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USPshnik [31]
3 years ago
14

What is the density of a liquid if the volume is 25 mL and the mass is 20.0 g?

Chemistry
1 answer:
LenKa [72]3 years ago
3 0

Answers:  

                   Density = 0.8 g/mol.        

Given data:

                   v = 25 ml

                    m = 20 g

                    δ = ?

Solution:

               Formula for calculating density is given as,

                Density = Mass / Volume    

                 putting values  

                 Density = 20.0 g / 25 ml

                  Density = 0.8 g/mol.

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Explain how the equation for GPE = force x distance.
Mkey [24]
GPE is the gravitational Potential Energy which is given by mgh.

mg is the gravitational force(a force) and h is the height of the object(or distance of the object from earth's surface)

SO GPE = mg (force) x h (distance)
4 0
3 years ago
For an ideal gas condition, what is the mass (g) of N2 if the pressure is 2.0 atm, the volume is 25 mL and the temperature is 29
Alchen [17]

Answer:

THE MASS OF NITROGEN GAS IN THIS CONDITIONS IS 0.0589 g

Explanation:

In an ideal condition

PV = nRT or PV = MRT/ MM where:

M = mass = unknown

MM =molar mass = 28 g/mol

P = pressure = 2 atm

V = volume = 25 mL = 0.025 L

R = gas constant = 0.082 L atm/mol K

T = temperature = 290 K

n = number of moles

The gas in the question is nitrogen gas

Molar mass of nitrogen gas = 14 * 2 = 28 g/mol

Then equating the variables and solving for M, we have

M = PV MM/ RT

M = 2 * 0.025 * 28 / 0.082 * 290

M = 1.4 / 23.78

M = 0.0589 g

The mass of the nitrogen gas at ideal conditions of 2 atm, 25 mL volume and 290 K temperature is 0.0589 g

3 0
3 years ago
A + B = AB
Ahat [919]

The greatest amount of AB would be produced if the equilibrium constant of the reaction is equal to 1.0 \;X \;10^5. Hence, option D is correct.

<h3>What is an equilibrium constant?</h3>

A number that expresses the relationship between the amounts of products and reactants present at equilibrium in a reversible chemical reaction at a given temperature.

The equilibrium constant expression is a mathematical relationship that shows how the concentrations of the products vary with the concentration of the reactants.

If the value of K is greater than 1, the products in the reaction are favoured. If the value of K is less than 1, the reactants in the reaction are favoured.

Hence, option D is correct.

Learn more about the equilibrium constant here:

brainly.com/question/10038290

#SPJ1

7 0
2 years ago
(Only answer if you’re for certain) Which type of molecule is shown below?
polet [3.4K]

i believe B is the answer

4 0
3 years ago
Read 2 more answers
At a certain temperature this reaction follows second-order kinetics with a rate constant of 14.1·M−1s−1 : →2SO3g+2SO2gO2g Suppo
RoseWind [281]

Answer:

[SO_3]=0.25M

Explanation:

Hello there!

In this case, since the integrated rate law for a second-order reaction is:

[SO_3]=\frac{[SO_3]_0}{1+kt[SO_3]_0}

Thus, we plug in the initial concentration, rate constant and elapsed time to obtain:

[SO_3]=\frac{1.44M}{1+14.1M^{-1}s^{-1}*0.240s*1.44M}\\\\

[SO_3]=0.25M

Best regards!

4 0
2 years ago
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