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Sunny_sXe [5.5K]
3 years ago
9

G the ksp of calcium hydroxide, ca(oh)2, is 5.02 × 10-6. calculate the molar solubility of this compound.

Chemistry
1 answer:
g100num [7]3 years ago
7 0
<span>When calcium hydroxide dissolves, it dissociates into Ca(OH)2 = Ca2+ and 2OH- Let's assign the variable X for the solubility of Ca2+ and OH I.e Ca2+ = X and 2OH- = 2X Then Ksp = [Ca2+][OH-]^2 So we have (X) (2X)^2 = 5.02 * 10^(-6) 4X^3 = 5.02 * 10 ^(-6) X^3 = 5.02 * 10^(-6) / 4 X^3 = 0.003110 X = 0.1459</span>
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E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}

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