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Burka [1]
3 years ago
8

The steps to balancing a neutralization reaction when given a verbal description can be summarized as follows: Write the chemica

l formulas for the reagents. Write the chemical formulas for the products. Balance each element on each side of the reaction arrow by adding coefficients to the reactants and products. The antacid Brioschi, which has been used to relieve heartburn, is mainly sodium bicarbonate. Predict the products, then write the balanced neutralization reaction for the antacid Brioschi in the stomach where the main acid present is hydrochloric acid, HCl. Express your answer as a chemical equation.
Chemistry
1 answer:
HACTEHA [7]3 years ago
7 0

Answer:

NaHCO3 + HCl ——-> NaCl + H2O + CO2

Explanation:

A neutralization reaction is a chemical reaction between an alkali and an acid to give salt and water as the product.

In the case of carbonates and bicarbonates, an additional product is added. This additional product is carbon iv oxide.

Hence a neutralization reaction involving an acid and a carbonate or bicarbonate would yield water, carbon iv oxide and a salt as the product.

When brioschi reacts with hydrochloric acid, the products are sodium chloride, water and carbon iv oxide.

The equation of the reaction is shown below:

NaHCO3 + HCl ——> NaCl + H2O + CO2

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masya89 [10]

(A) 7.28\cdot 10^{-10} m

The De Broglie wavelength of an electron is given by

\lambda=\frac{h}{p} (1)

where

h is the Planck constant

p is the momentum of the electron

The electron in this problem has a speed of

v=1.00\cdot 10^6 m/s

and its mass is

m=9.11\cdot 10^{-31} kg

So, its momentum is

p=mv=(9.11\cdot 10^{-31} kg)(1.00\cdot 10^6 m/s)=9.11\cdot 10^{-25}kg m/s

And substituting into (1), we find its De Broglie wavelength

\lambda=\frac{6.63\cdot 10^{-34}Js}{9.11\cdot 10^{-25} kg m/s}=7.28\cdot 10^{-10} m

(B) 1.16\cdot 10^{-34}m

In this case we have:

m = 0.143 kg is the mass of the ball

v = 40.0 m/s is the speed of the ball

So, the momentum of the ball is

p=mv=(0.143 kg)(40.0 m/s)=5.72 kg m/s

And so, the De Broglie wavelength of the ball is given by

\lambda=\frac{h}{p}=\frac{6.63\cdot 10^{-34} Js}{5.72 kg m/s}=1.16\cdot 10^{-34}m

(C) 9.02\cdot 10^{-9}m

The location of the first intensity minima is given by

y=\frac{L\lambda}{a}

where in this case we have

y=0.492 cm = 4.92\cdot 10^{-3} m

L = 1.091 is the distance between the detector and the slit

a=2.00\mu m=2.00\cdot 10^{-6}m is the width of the slit

Solving the formula for \lambda, we find the wavelength of the electrons in the beam:

\lambda=\frac{ya}{L}=\frac{(4.92\cdot 10^{-3}m)(2.00\cdot 10^{-6} m)}{1.091 m}=9.02\cdot 10^{-9}m

(D) 7.35\cdot 10^{-26}kg m/s

The momentum of one of these electrons can be found by re-arranging the formula of the De Broglie wavelength:

p=\frac{h}{\lambda}

where here we have

\lambda=9.02\cdot 10^{-9}m is the wavelength

Substituting into the formula, we find

p=\frac{6.63\cdot 10^{-34}Js}{9.02\cdot 10^{-9}m}=7.35\cdot 10^{-26}kg m/s

7 0
3 years ago
As a substance changes from a liquid to a gas, the average distance between molecules..
dimulka [17.4K]

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the answer is B because I jus did that

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Bezzdna [24]
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0.50 is the answer on edge

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