Answer:
no
Explanation:
Small marble chips reacts faster
Answer:

Explanation:
Hello,
In this case, the enthalpy of combustion is understood as the energy released when one mole of fuel, in this case octene, is burned in the presence of oxygen and is computed with the enthalpies of formation of the fuel, carbon dioxide and water as shown below (oxygen is circumvented as it is a pure element):

Thus, since we already know the enthalpy of combustion of the fuel, for carbon and water we have -393.5 and -241.8 kJ/mol respectively, thereby, the enthalpy of combustion turns out:

Best regards.
The neutron, Proton, and Electron
Answer:
1. Synthesis
2. Decomposition
3. Single replacement
4. Synthesis
5. Decomposition
6. Synthesis
Explanation:
Kind of a hard picture to look at but let me define each chemical reaction:
Synthesis:
a + b ---> ab In synthesis elements/compounds come together to form new compounds
Decomposition:
ab ---> a + b In decomposition a compound breaks down to form 2 elements/compounds
Single replacement:
a + bc ---> b + ac In a single replacement one element/compound takes the place of another element/compound.
Double replacement
ab + cd ---> ad + bc In a double replacement 2 compounds exchange different elements/compounds.
Now, let's go through the assignment
1. P + O2 --> P4O10 This is a synthesis reaction because the two elements (P and O) came together to form one compound.
2. HgO ---> Hg + O2 This is a decomposition reaction because HgO broke into separate elements Hg and O.
3. Cl2 + NaBr ---> NaCl + Br2 This is a single replacement reaction because chlorine (Cl) replaced the spot of bromine (Br) to bond with sodium (Na).
4. Mg + O2 ---> MgO This is a synthesis reaction because two elements (Mg and O) came together to form one compound.
5. Al2O3 ---> Al + O2 This is a decomposition reactions because Al2O3 broke into separate elements Al and O.
6. H2 + N2 ---> NH3 This is a synthesis reaction because two elements (H and N) came together to form one compound.
<em>I hope this helps!!</em>
<em>- Kay :)</em>