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jarptica [38.1K]
2 years ago
15

The mass of a jar of sugar is 11. 9 kg. What is the total mass of 13 jars of sugar?.

Chemistry
1 answer:
Masteriza [31]2 years ago
5 0

Answer:

154.7

Explanation:

11.9kg x 13 = 154.7

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Which element would react faster with oxygen because of the properties it possesses?
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Phosphoric acid is a triprotic acid with the following pKa values:
lisabon 2012 [21]

Answer:

Mass NaH₂PO₄ = 1.920 g

Mass Na₂HPO₄ = 4.827 g

Explanation:

For a buffer solution we know its pH can be calculated from the Henderson-Hasselbach formula:

pH = pKa + log [A⁻]/[HA]

where [A⁻] and [HA] are the concentrations of the weak acid and its conjugate base in the buffer.

We want to prepare a buffer at pH 7.540 so we have chosen salts NaH₂PO₄ and Na₂HPO₄ as the weak acid and conjugate base respectively.

To calculate the mass of these salts we need to compute their ratio in the Henderson- Hasselbach equation .

Now since we are asked to determine the masses of NaH₂PO₄  and  Na₂HPO₄ and we know we want to prepare 1.000 L of a 0.05 M phosphate buffer, we can setup a system of 2 equations with two unknowns from the ratio mentioned above:

pH = pKa + log [A⁻]/[HA]

7.540 = 7.198 + log[HPO₄²⁻] / [H₂PO₄ ⁻]

0.342 = log[HPO₄²⁻] / [H₂PO₄ ⁻]

taking inverse log function to both sides of this equation:

2.198 = [HPO₄²⁻] / [H₂PO₄ ⁻]

but this is also equivalent to

2.198 = mol HPO₄²⁻ / mol H₂PO₄⁻   (M = mol/V)

We also know that in 1 liter of 0.05 M phosphate, we have 0.05 total mol HPO₄²⁻  and H₂PO₄⁻  , thus

mol HPO₄²⁻ + mol H₂PO₄⁻  = 0.05 mol

2.198 = mol HPO₄²⁻ / mol H₂PO₄⁻  

solving this system of equations calling  x = mol HPO₄²⁻ and y = mol H₂PO₄⁻ , we have:

2.198 = x /y    ⇒ x = 2.198y

x + y = 0.05

2.198y + y = 0.05

3.198 y = 0.05 ⇒ y = 0.05 / 3.198 = 0.016

x = 0.05 - 0.016 = 0.034

and the masses can be calculated from the molar masses ( 141.96 g/mol Na₂HPO₄ and 119.98 g/mol NaH₂PO₄

mol HPO₄²⁻ = 0.034 mol x 141.96 g/mol = 4.827 g

mol H₂PO₄⁻ =  0.016 mol x 119.98 g/mol = 1.920 g

6 0
3 years ago
a given sample of a gas has a volume of 3.0 L at a pressure of 4.0 atm. If the temperature remains constant and the pressure is
pentagon [3]

Answer:-

2.0 L

Explanation:-

Initial Volume = V 1 = 3.0 L

Initial Pressure P 1 = 4.0 atm

New pressure P 2 = 6.0 atm

Using boyle's law

P1 V1 = P2 V2

New Volume V2 = P1 V1 / P2

= 4.0 atm x 3.0 L / 6.0 atm

= 2 .0 L

3 0
3 years ago
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